Roughly 4200 seconds, since the specific heat of water is around 4.2J/gK (ie it takes 4.2 joules to raise 1 gram by 1 Kelvin); 1 litre = 1000 grams, 1 Celcius (centigrade) = 1K, 1W = 1J/s.
It takes 1000 calories to heat 1 litre of water 1 degree C.
Yes, your body uses a thermal energy known as caloric energy called "calories." A calorie is the amount of thermal energy required to heat one gram of water by one degree centigrade.
Since watt is a unit of power (how fast energy is transferred), you can do this with almost any amount of power - as little or as much as you want, depending on how fast you want to heat the water. The time it takes will depend on the initial temperature, the amount of water, and the power.
2.4705 watts/hour
A quart of water is 946.35 cubic centimeters and since density of water is 1 gram per cubic centimeter the weight of a quart of water is 946.35 grams. Heat required = (mass) x (specific heat of substance) x (temperature differential) In our case it would be 946.35 x 1 x 38(assumed degrees centigrade) = 35961.3 cals
The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.
195 joule..
0 degree centigrade after giving the latent heat.
one calorie is enough to heat one gram of water by one degree Centigrade.
4186 Joules per liter per deg C. Not clear if we are raising the temperature BY 135 deg or TO 135 deg. So the answer is 4186 x 100 x rise in temperature. (Joules).
It takes 1000 calories to heat 1 litre of water 1 degree C.
300 calories, which is equal to about 1255.2 joules
A calorie is the amount of heat required to warm 1 gram of water one degree Centigrade. A Calorie spelt with a big "C" is a kilocalorie and is used in evaluating food energy. It is the heat required to raise 1 kilogram of water one Centigrade degree. On an energy basis a calorie is 41 840 000 ergs.
292 kj
The calorific value of water is 80cal/degree. so it takes 60*80=2400cal of heat.
1 litre for 1 degree in 1hour is 1,16 kW/h
Heat of vaporization of water is 2.26 x 106 joules per kg. Therefore 1 gram of water will need 2.26 x 103 joules.