A centimetre is a unit of distance. A litre is a unit of volume. The two units are therefore incompatible.
1 L = 1000 mL = 1000 cm cubed
Any number greater than or equal to 4*sqrt(45) cm or 26.83 cm (approx). To see that, suppose L ≥ sqrt(45) cm be the length of the rectangle and let B = 45/L cm Then Area = L*B = L*(45/L) = 45 cm2 If L = 9cm, then B = 45/9 = 5 cm and then perimeter = 2*(L+B) = 28 cm If L = 90 cm, then B = 0.5 cm and P = 181 cm If L = 900 cm, then B = 0.05 cm and P = 1800.1 cm If L = 9000000 cm then B = 0.000005 cm and P = 18000000.00001 cm As can be seen, the perimeter can be increased without limit.
5.5 L
The length of the diagonal is not enough to determine the dimensions of the rectangle. Take any length W such that 0<W<sqrt(132/2) that is, 0<W<9.192 cm. And let L = sqrt(132 - W2) cm. Then 9.192<L<13 so that any combination of W and L is unique. There are infinitely many possible values for W and so infinitely many different combinations for W and L. That is, infinitely many rectangles whose width is W cm and length is L cm. And, since, L2 = 132 - W2, L2 + W2 = 132 so the diagonal is 13 cm.
Conversion of m to cm and mm: 1 m = 100 cm; 1 m = 1000 mmConversion of l to ml: 1 L = 1000 ml
53 centimetres = 20.87 inches
1 cm = 0.01 m So, 53 cm = 0.53 m
530mm
By unit of length and distance and conversion ,we can say that 1 dm=10 cm 53 cm=5.3 dm
1 L = 1000 mL = 1000 cm cubed
100 centimetres = 1 metre so 53 cm = 53/100 = 0.53 metres. Simple!
5 ft 3 in = 160.02 cm
77cm by 53 cm equates to about 632.6 square inches.
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.
53 cm
30.3" x 20.9" (77 cm x 53 cm), hope you looking for that
53 centimeters = 1.74 feet.