The length of the diagonal is not enough to determine the dimensions of the rectangle.
Take any length W such that 0<W<sqrt(132/2) that is, 0<W<9.192 cm.
And let L = sqrt(132 - W2) cm.
Then 9.192<L<13 so that any combination of W and L is unique.
There are infinitely many possible values for W and so infinitely many different combinations for W and L. That is, infinitely many rectangles whose width is W cm and length is L cm.
And, since, L2 = 132 - W2, L2 + W2 = 132 so the diagonal is 13 cm.
13cm*13cm =169 square cm.
The diagonal is 7.21 feet.
Given: p = 26cm and 2x width - 5cm = length p = 2(a+b) = 26cm; a+b = 13cm 2x6-5=7 The sides of the rectangle are: width 6cm and length 7cm
A rectangle has dimensions 7 ft x 12 ft. Which of the dimensions describe a rectangle that is similar to this rectangle?
The diagonal would be 12.53 meters.
Yes if the dimensions were 3cm by 13cm
The diagonal is 100'
The diagonal is 47.707'
The diagonal is 221.2 inches long.
26.4 inches for the diagonal.
157.6102789 inches
4cm by 13cm
If they are the dimensions of a rectangle then use Pythagoras' theorem to find the length of the diagonal.
152feet 3.79inches (rounded)
13cm*13cm =169 square cm.
If it's the dimensions of a rectangle then by using Pythagoras' theorem its diagonal is 40
20 ft