The length of the diagonal is not enough to determine the dimensions of the rectangle.
Take any length W such that 0<W<sqrt(132/2) that is, 0<W<9.192 cm.
And let L = sqrt(132 - W2) cm.
Then 9.192<L<13 so that any combination of W and L is unique.
There are infinitely many possible values for W and so infinitely many different combinations for W and L. That is, infinitely many rectangles whose width is W cm and length is L cm.
And, since, L2 = 132 - W2, L2 + W2 = 132 so the diagonal is 13 cm.
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13cm*13cm =169 square cm.
Given: p = 26cm and 2x width - 5cm = length p = 2(a+b) = 26cm; a+b = 13cm 2x6-5=7 The sides of the rectangle are: width 6cm and length 7cm
A rectangle has dimensions 7 ft x 12 ft. Which of the dimensions describe a rectangle that is similar to this rectangle?
The diagonal would be 12.53 meters.
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet