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The length of the diagonal is not enough to determine the dimensions of the rectangle.

Take any length W such that 0<W<sqrt(132/2) that is, 0<W<9.192 cm.

And let L = sqrt(132 - W2) cm.

Then 9.192<L<13 so that any combination of W and L is unique.

There are infinitely many possible values for W and so infinitely many different combinations for W and L. That is, infinitely many rectangles whose width is W cm and length is L cm.

And, since, L2 = 132 - W2, L2 + W2 = 132 so the diagonal is 13 cm.

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10y ago
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Q: What are the dimensions of rectangle if the diagonal is 13cm?
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