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If you are looking to create codes using the digits 0, 1, 2, 3, and 4 without repetition, you would be creating permutations. The number of permutations of n items taken r at a time is given by the formula P(n,r) = n! / (n-r)!. In this case, you have 5 digits to choose from (n=5) and you want to create a code with all 5 digits (r=5). Therefore, the number of codes you can make is 5! / (5-5)! = 5! / 0! = 5! = 5 x 4 x 3 x 2 x 1 = 120.

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ProfBot

7mo ago

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