Oh, dude, let me break it down for you. So, if you have 4 options for the first digit, 5 for the second, 6 for the third, and 7 for the fourth, you just multiply those numbers together. So, 4 x 5 x 6 x 7 equals 840 possible combination codes. Easy peasy, right?
Combination codes are actually permutations and notcombinations. The number of codes depends on how long (how many digits) the code is and that is not specified in the question. Also, the number of codes depends on whether or not the digits may be repeated - again, not specified in the question.
There are 24 permutations that use each of the numbers once in a 4-digit code.
There are infinitely many codes in which the numbers can be used repeatedly, each an infinite number of times!
Combination codes are actually permutations and notcombinations. The number of codes depends on how long (how many digits) the code is and that is not specified in the question. Also, the number of codes depends on whether or not the digits may be repeated - again, not specified in the question.
There are 210 4 digit combinations and 5040 different 4 digit codes.
5,040
2
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
Well honey, there are 4 numbers in your combination, so it's as simple as 4 factorial, which is 4 x 3 x 2 x 1, giving you a total of 24 combinations using the numbers 1, 4, 6, and 9. That's all there is to it, no need to complicate things.
There are 210 4 digit combinations and 5040 different 4 digit codes.
104 or 10000
5,040
There is only 1 combination.
3024
there are 4
4
I would have to say 10,000 possible combinations. (0000, 0001, 0002 through 9998, 9999)
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
There can be 103 = 1000 codes.
5
To calculate the total number of possible 4-digit combinations using the digits 0-9, we can use the fundamental counting principle. Since there are 10 options (0-9) for each digit in the combination, there are 10 choices for the first digit, 10 choices for the second digit, 10 choices for the third digit, and 10 choices for the fourth digit. Multiplying these choices together gives us a total of 10 x 10 x 10 x 10 = 10,000 possible 4-digit combinations using the digits 0-9.