0
To calculate the number of combination codes using the numbers 4, 5, 6, and 7, we use the formula for permutations of a set of objects. Since there are 4 numbers to choose from and we are using all of them, the formula for permutations of n objects taken all at a time is n! (n factorial). Therefore, the number of combination codes using 4, 5, 6, and 7 would be 4! = 4 x 3 x 2 x 1 = 24.
Still curious? Ask our experts.
Chat with our AI personalities
Jordan
Ezra
ViviCombination codes are actually permutations and notcombinations. The number of codes depends on how long (how many digits) the code is and that is not specified in the question. Also, the number of codes depends on whether or not the digits may be repeated - again, not specified in the question.
There are 24 permutations that use each of the numbers once in a 4-digit code.
There are infinitely many codes in which the numbers can be used repeatedly, each an infinite number of times!
Combination codes are actually permutations and notcombinations. The number of codes depends on how long (how many digits) the code is and that is not specified in the question. Also, the number of codes depends on whether or not the digits may be repeated - again, not specified in the question.
Add your answer:
Earn +20 pts
How many possible 4 digit combinations are there using 0-9. how many different combination codes are possible?
There are 210 4 digit combinations and 5040 different 4 digit codes.
How many different binary codes can be represented in 2 bits?
2
If using numbers 0 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
How many 4 number combinations are their using numbers 1469?
Well honey, there are 4 numbers in your combination, so it's as simple as 4 factorial, which is 4 x 3 x 2 x 1, giving you a total of 24 combinations using the numbers 1, 4, 6, and 9. That's all there is to it, no need to complicate things.
What are all the possible 4 digit codes using the numbers 0 to 9 without using the same digit twice in each code?
Any 4 from 10 in any order = 10 x 9 x 8 x 7 = 5040
