Combination codes are actually permutations and notcombinations. The number of codes depends on how long (how many digits) the code is and that is not specified in the question. Also, the number of codes depends on whether or not the digits may be repeated - again, not specified in the question.
There are 24 permutations that use each of the numbers once in a 4-digit code.
There are infinitely many codes in which the numbers can be used repeatedly, each an infinite number of times!
There are 210 4 digit combinations and 5040 different 4 digit codes.
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In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
To calculate the number of 4-number combinations using the numbers 1, 4, 6, and 9 without repetition, you can use the permutation formula. Since there are 4 options for the first number, 3 options for the second number, 2 options for the third number, and 1 option for the fourth number, you would multiply these numbers together: 4 x 3 x 2 x 1 = 24. Therefore, there are 24 different 4-number combinations using the numbers 1, 4, 6, and 9.
Any 4 from 10 in any order = 10 x 9 x 8 x 7 = 5040
There are 210 4 digit combinations and 5040 different 4 digit codes.
104 or 10000
There is only 1 combination.
3024
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there are 4
I would have to say 10,000 possible combinations. (0000, 0001, 0002 through 9998, 9999)
There can be 103 = 1000 codes.
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120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
The number of 4 digit codes, using different digits, is 10*9*8*7 = 5040. However, computer passwords can, usually, have repeated digits and, if that is allowed, you can have 104 = 10000 codes.
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