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There are 9C3 = 84 combinations.

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10y ago

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Related Questions

How many four digit combnation can be made from 0-9?

9


How many possible 4 digit combinations are there using 0-9 with no duplicates?

There are 5,040 combinations.


How many 2 digit combinations can be made from 0 to 9 digits?

45 In combinations, the order of the digits does not matter so that 12 and 21 are considered the same.


How many 3 digit combinations 000 to 999 can be made?

There are a total of 1,000 three-digit combinations from 000 to 999. This includes all combinations where the digits can range from 0 to 9, allowing for repetitions. Each of the three digit positions can have 10 possible values (0-9), leading to (10 \times 10 \times 10 = 1,000) combinations.


How many possible 4 digit combinations are there using 0-9. how many different combination codes are possible?

There are 210 4 digit combinations and 5040 different 4 digit codes.


How many 6 digit combinations can be made from digits 0 to 9?

10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.


How many three digit combinations can be made?

To find the number of three-digit combinations, we consider the digits from 000 to 999. Each digit can range from 0 to 9, giving us 10 options for each of the three digits. Therefore, the total number of three-digit combinations is (10 \times 10 \times 10 = 1,000).


How many 6 digit combinations can be made from 0 to 99?

Oh, what a happy little question! There are 100,000 different 6-digit combinations that can be made from 0 to 99. It's like painting a beautiful landscape with numbers - each combination is unique and special in its own way. Just imagine all the possibilities and let your creativity flow!


If using numbers 0 through 9 how many different 4 digit combinations can be made?

To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.


If using numbers 0 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?

In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.


If using 0 though 9 how may many different 9 digit combinations can be made?

I believe the answer would be 10^9 or 1,000,000,000


How many different three digit number combinations can be made with 0-9 with no repeat numbers when order of the number does not matter?

9