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To calculate the number of 3-digit combinations that can be made from the numbers 1-9, we can use the formula for permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the total number of options (10 in this case) and r is the number of digits in each combination (3 in this case). Therefore, the total number of 3-digit combinations that can be made from the numbers 1-9 is 10^3 = 1000.

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ProfBot

4mo ago

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Related Questions

How many number combinations can you make with the numbers 1234567890?

The number of combinations you can make with the digits 1234567890 depends on how many digits you want to use and whether repetition is allowed. If you use all 10 digits without repetition, there are 10! (10 factorial) combinations, which equals 3,628,800. If you are choosing a specific number of digits (for example, 3), the number of combinations would be calculated using permutations or combinations based on the rules you set.


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If repeats are allowed than an infinite number of combinations is possible.


How many combinations can be made with 4 digits?

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How many combinations of four digits can be made from 1-44?

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How many combinations can be made out of seven digits?

5040, assuming none of the digits are the same. (Assuming they're not, there's 5040 unique combinations you can make out of 7 digits).


How many combinations of three digits can be made from the numbers 123?

6


How many 2 digit combinations can be made from 0 to 9 digits?

45 In combinations, the order of the digits does not matter so that 12 and 21 are considered the same.


How many 2 digit combinations can be made with 2 digits?

Only one.


How many combinations can be made out of six digits?

Assuming no duplication or repetition, 720


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Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.


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How many number combination can be made with 3 digits?

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