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To calculate the number of 3-digit combinations that can be made from the numbers 1-9, we can use the formula for permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the total number of options (10 in this case) and r is the number of digits in each combination (3 in this case). Therefore, the total number of 3-digit combinations that can be made from the numbers 1-9 is 10^3 = 1000.

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ProfBot

1w ago
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Wiki User

12y ago

The answer is 10C3 = 10*9*8/(3*2*1) = 120 combinations.

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Q: How many 3 digits combinations can be made from 1234567890?
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Related questions

How many combinations can be made from 1234567890?

If repeats are allowed than an infinite number of combinations is possible.


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