It depends how many numbers are in your combinations:
0 or 24 there is 1
1 or 23 there are 24
2 or 22 there are 276
3 or 21 there are 2,024
4 or 20 there are 10,626
5 or 19 there are 42,504
6 or 18 there are 134,596
7 or 17 there are 346,104
8 or 16 there are 735,471
9 or 15 there are 1,307,504
10 or 14 there are 1,961,256
11 or 13 there are 2,496,144
12 there are 2,704,156
If by combinations you do not mean the mathematical selection of a subset of items from a set of items (where the order doesn't matter) but how many ways are there of arranging 24 numbers then there are:
24! = 620,448,401,733,239,439,360,000 ways.
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24C7 = 24!/((24-7)!7!) = 346,104.
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
Well, honey, since you're picking 12 numbers out of 24, you're looking at a combination situation. The formula for combinations is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items you're choosing. So, in this case, it would be 24C12 = 24! / (12!(24-12)!). Plug that into a calculator, and you'll get your answer. Math can be a real hoot, can't it?
Three combinations: 23, 24 and 34
Many combinations of number have a mean of 24. For example, 22, 23, 24, 25, and 26 have a mean of 24. To find a mean, add the numbers and divide by the count of the numbers (the number of observations): (22 + 23 + 24 + 25 + 26) ÷ 5 = 24 ...but so does this: (20 + 22 + 24 + 26 + 28) ÷ 5 = 24 ...and this: (-96 + -4 + 30 + 72 + 118) ÷ 5 = 24 ...and so on...