It depends how many numbers are in your combinations:
0 or 24 there is 1
1 or 23 there are 24
2 or 22 there are 276
3 or 21 there are 2,024
4 or 20 there are 10,626
5 or 19 there are 42,504
6 or 18 there are 134,596
7 or 17 there are 346,104
8 or 16 there are 735,471
9 or 15 there are 1,307,504
10 or 14 there are 1,961,256
11 or 13 there are 2,496,144
12 there are 2,704,156
If by combinations you do not mean the mathematical selection of a subset of items from a set of items (where the order doesn't matter) but how many ways are there of arranging 24 numbers then there are:
24! = 620,448,401,733,239,439,360,000 ways.
24C7 = 24!/((24-7)!7!) = 346,104.
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
Well, honey, since you're picking 12 numbers out of 24, you're looking at a combination situation. The formula for combinations is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items you're choosing. So, in this case, it would be 24C12 = 24! / (12!(24-12)!). Plug that into a calculator, and you'll get your answer. Math can be a real hoot, can't it?
Three combinations: 23, 24 and 34
Many combinations of number have a mean of 24. For example, 22, 23, 24, 25, and 26 have a mean of 24. To find a mean, add the numbers and divide by the count of the numbers (the number of observations): (22 + 23 + 24 + 25 + 26) ÷ 5 = 24 ...but so does this: (20 + 22 + 24 + 26 + 28) ÷ 5 = 24 ...and this: (-96 + -4 + 30 + 72 + 118) ÷ 5 = 24 ...and so on...
24C7 = 24!/((24-7)!7!) = 346,104.
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
There are 24C12 = 24*23*...*13/(12*11*...*1) = 2,704,156 combinations.
4!=4x3x2x1=24
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
24
4! = 4*3*2*1 = 24 of them.
there are altogether 24 numbers between 9 and 32. by using nCr, 24C4 = 10626
it is hard to say there are lot of combinations belive or not * * * * * If the previous answerer thinks 15 is a lot then true. There are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations. Not so hard to say!
any 4 from 7 is 35, in any order is 35 x 24 ie 840
Well, honey, since you're picking 12 numbers out of 24, you're looking at a combination situation. The formula for combinations is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items you're choosing. So, in this case, it would be 24C12 = 24! / (12!(24-12)!). Plug that into a calculator, and you'll get your answer. Math can be a real hoot, can't it?
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb