it is hard to say there are lot of combinations belive or not
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If the previous answerer thinks 15 is a lot then true. There are
1 combination of 4 numbers out of 4,
4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4,
4 combinations of 1 number out of 4.
A grand total of 15 (= 24-1) combinations. Not so hard to say!
4*3*2*1 = 24 different combinations.
The number of combinations is 10C4 = 10*9*8*7/(4*3*2*1) = 210
There are 120 permutations and 5 combinations.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
To calculate the number of 4-number combinations from 1 to 20, we can use the formula for combinations, which is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items to choose. In this case, n = 20 and r = 4. Plugging these values into the formula, we get 20C4 = 20! / (4!(20-4)!) = 4845. Therefore, there are 4845 different 4-number combinations possible from the numbers 1 to 20.
There are 15 combinations.
If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
The number of 4 different book combinations you can choose from 6 books is;6C4 =6!/[4!(6-4)!] =15 combinations of 4 different books.
10,000 * * * * * WRONG! That is the number of permutations, NOT the number of combinations. The number of combinations denoted by nCr = n!/[r!*(n-r)!] = 10!/[4!*6!] = 10*9*8*7/(4*3*2*1) = 210
There are 1285C4 = 1285*1284*1283*1282/(4*3*2*1) = 113076300485 combinations.
2^n possible combinations