To determine the number of combinations of 3 words, we need to know the total number of words available. Let's say we have a pool of n words. The formula to calculate the number of combinations of 3 words without repetition is n! / (3!(n-3)!), where "!" denotes factorial. This formula accounts for the number of ways we can select 3 words from a pool of n without repetition.
There are 6C3 = 20 such combinations.
There are 5C3 = 10 combinations.
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
There are 9C3 = 84 combinations.
9
There are: 35C3 = 6545 combinations
233 = 18 combinations.
There are 5C3 = 10 combinations.
There are 6C3 = 20 such combinations.
3 items each in 3 categories gives 3*3*3 = 27 possible combinations.
There are 9C3 = 84 combinations.
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9
There are about 57 words that are combinations of the letters A through G There are about 57 words that are combinations of the letters A through G
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
4 pitchers * 3 catchers = 12 combinations
7*3*4 = 84 combinations.