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How many sides on a polygon with the sum of the interior angles is 6840?
To find the number of sides on a polygon with a sum of interior angles of 6840 degrees, we can use the formula: (n-2) * 180 = 6840, where n represents the number of sides. Solving for n, we get n = (6840 / 180) + 2 = 38. Therefore, the polygon has 38 sides.
What is the sum of a interior angle of a polygon with 38 sides?
Sum of interior angles of a 38 sided polygon: (38-2)*180 = 6480 degrees
What is the number of sides of a regular polygon if one angle measures 171 degrees?
The formula to find the sum of the angles of a polygon is: 180(n - 2) Since we know that one angle of this regular polygon is 171 degrees, we can find what kind of polygon it will be, using the formula: 180(n - 2) = 171n 180n - 360 = 171n 180n - 171n = 360 9n = 360 n = 360/9 n = 40 Thus the polygon is a 40-sided polygon. Check: 180(40 - 2) = 180(38) = 6840, which is the sum of the angles of the polygon. 6840/40 = 171 degrees, which is the measure of one of the angles of that polygon .
What is the answer to x-25 equals 38?
x - 25 = 38 x - 25 + 25 = 38 + 25 (add 25 to both sides) x = 63
How do you solve the equation 5n - 7 equals 38?
To solve the equation 5n - 7 = 38, do whatever you do to one side of the equals sign to the other. So, add 7 to both sides. 5n = 38. Now divide both sides by 9. 5 = 9. To check your answer, replace the n with 9 and solve the equation. 5 x 9 - 7 = 38. Do the multiplacation first. 45 - 7 = 38. 38 = 38. The answer is correct.
