Sum of interior angles of a 38 sided polygon: (38-2)*180 = 6480 degrees
If the polygon has n sides, the sum of the interior angles is (n - 2)*180 degrees. So (n - 2)*180 = 6840 (n - 2) = 6840/180 = 38 So n = 38 + 2 = 40 sides.
The formula to find the sum of the angles of a polygon is: 180(n - 2) Since we know that one angle of this regular polygon is 171 degrees, we can find what kind of polygon it will be, using the formula: 180(n - 2) = 171n 180n - 360 = 171n 180n - 171n = 360 9n = 360 n = 360/9 n = 40 Thus the polygon is a 40-sided polygon. Check: 180(40 - 2) = 180(38) = 6840, which is the sum of the angles of the polygon. 6840/40 = 171 degrees, which is the measure of one of the angles of that polygon .
x - 25 = 38 x - 25 + 25 = 38 + 25 (add 25 to both sides) x = 63
To solve the equation 5n - 7 = 38, do whatever you do to one side of the equals sign to the other. So, add 7 to both sides. 5n = 38. Now divide both sides by 9. 5 = 9. To check your answer, replace the n with 9 and solve the equation. 5 x 9 - 7 = 38. Do the multiplacation first. 45 - 7 = 38. 38 = 38. The answer is correct.
38 diagonals
Sum of interior angles of a 38 sided polygon: (38-2)*180 = 6480 degrees
If the polygon has n sides, the sum of the interior angles is (n - 2)*180 degrees. So (n - 2)*180 = 6840 (n - 2) = 6840/180 = 38 So n = 38 + 2 = 40 sides.
A 38-sided polygon would be named a triacontaoctagon.
The sum of the interior angles of a polygon is 2n - 4 right angles where n is the number of sides. When n = 21 then 2n - 4 = 42 - 4 = 38 right angles = 38 x 90 = 3420°. NOTE : If the polygon is a regular polygon then each interior angle measures 3420 ÷ 21 = 162.86°.
It contains 36 triangles
38 sides
The sum of the interior angles of a polygon can be calculated using the formula: [ \text{Sum of interior angles} = (n - 2) \times 180^\circ ] where (n) is the number of sides of the polygon. For a polygon with 40 sides ((n = 40)): [ \text{Sum of interior angles} = (40 - 2) \times 180^\circ = 38 \times 180^\circ = 6840^\circ ] Thus, the sum of the interior angles of a polygon with 40 sides is **6840 degrees Read more....tinyurl com/22enuvst
The perimeter of the larger polygon will have the same ratio to the perimeter of the smaller as the ratio of the corresponding sides. Therefore, the larger polygon will have a perimeter of 30(15/12) = 37.5, or 38 to the justified number of significant digits stated.
Providing that it is a regular 38 sided polygon then each interior angle will measure: 170o31'34.74''
an irregular polygon
The formula to find the sum of the angles of a polygon is: 180(n - 2) Since we know that one angle of this regular polygon is 171 degrees, we can find what kind of polygon it will be, using the formula: 180(n - 2) = 171n 180n - 360 = 171n 180n - 171n = 360 9n = 360 n = 360/9 n = 40 Thus the polygon is a 40-sided polygon. Check: 180(40 - 2) = 180(38) = 6840, which is the sum of the angles of the polygon. 6840/40 = 171 degrees, which is the measure of one of the angles of that polygon .