Sum of interior angles of a 38 sided polygon: (38-2)*180 = 6480 degrees
Yes and it has 52 sides
The answer is 11 sides If a polygon with 10 sides the sum of the interior angles are 1440° So 1440°+180°= 1620°
The method of finding the sum of the interior angles of a polygon is by multiplying the (number of sides)-2 by 180, so the sum of the interior angle measures in a 25-sided polygon would be 23*180, or 4140 degrees.
The sum of the EXTERIOR angles of a polygon is 360 degrees. The sum of the INTERIOR angles of a polygon with n sides is (n-2)*180 degrees. If it is a regular polygon, each interior angle is (n-2)/n*180 degrees.
A polygon with n sides inscribed in a circle has an angle sum of 180xn-360 So the problem is find n so that 180n-360=9000 => n=48 The regular polygon with an angle sum of 9000 has 48 sides
The sum of the interior angles of a polygon with n sides is 180*(n-2) degrees.
The polygon would have 10 sides.
(number of sides -2)*180 = sum of interior angles
8
7
6
15
There is no regular polygon with an interior angle of 20o. If the interior angle is 120o then there are six sides and the sum of the angles is 720o.
360 degrees
Yes and it has 52 sides
The answer is 11 sides If a polygon with 10 sides the sum of the interior angles are 1440° So 1440°+180°= 1620°
It will have 26 sides