16
There are 2 * 6 or 12 outcomes for flipping a coin and spinning a spinner that has 6 different colored sections.
6
The sample space is H1, H2, H3, H4, H5, T1, T2, T3, T4, T5.
9
We say that these are independent events, meaning that the outcome of rolling the cube does not influence what outcome of rotating the spinner. For each outcome of rolling the cube there are 10 outcomes from the spinner. We can therefore, multiply the numbers of possibilities: 6 * 10 = 60 One way of seeing this is to list the possible outcomes : C1 S1 C1 S2 C1 S3 . . . C1 S10 Notice that there are 10 spinner possibilities for one cube event. There are 5 more possible cube events, hence, 50 combination events.
There are 2 * 6 or 12 outcomes for flipping a coin and spinning a spinner that has 6 different colored sections.
If a spinner has six possible outcomes, then there are 36 (62) permutations of outcomes from spinning it twice.
Six times the number of different outcomes on the spinner.
6
There are 2*4*6 = 48 possible outcomes in total.
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There are 3 possible outcomes for each spin of the spinner. To find the total number of possible outcomes after spinning it four times, you would multiply the number of outcomes for each spin (3) by itself four times (3^4), resulting in 81 possible outcomes.
To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.
2
To calculate the probability of spinning a multiple of 3 on a spinner labeled 1 through 10, we first determine the total number of favorable outcomes. The multiples of 3 between 1 and 10 are 3, 6, and 9. Therefore, there are 3 favorable outcomes. Since there are a total of 10 equally likely outcomes on the spinner, the probability of spinning a multiple of 3 is 3/10 or 0.3.
You multiply the possibilities so 6 possibilities of the dice and the 10 possibilities of the spinner so in total there are 60 possible outcomes for this situation.
To determine the amount of possible outcomes, there must be a number of sections for each spinner