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If you spin the spinner two times what is the probability that the spinner will land on the black region twice?
To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.
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A five color spinner with equal sections of red blue green yellow and orange is spun What is the probability of getting no reds in six spins?
If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.
How many outcomes are possible if you spin the spinner 3 times?
You need to know how many outcomes you have. Is the spinner composed of colors, numbers, names? What categories does the spinner have?
What's the probability to get black jack?
A Black Jack is an Ace and a face card (Ten through King). The probability of drawing a Black Jack as the first two cards from a standard deck is 4 in 52 times 16 in 51, which is 0.0241 (Ace First), or 16 in 52 times 4 in 51, which is also 0.0241 (Ace Second).
The probability of rolling 5 40 times is 12 What is the probability of rolling 5 500 times?
Probability is a number between 0 and 1. The probability of an event cannot be 12.
What is the probability of failing 75 times on a 2 percent chance of success?
If the probability of succeeding is 2%, then the probability of failing is 98%. The probability, then, of failing 75 times is 98%75, which is 22%.
What is the probability of a number less than 6 on the number cube followed by a number equal to 6 on the spinner?
The probability is(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)
If the spinner is spun twice what is the probability that the arrow will stop on an even number both times?
It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...
You spin a spinner two times find the probability that the spinner stops on 3 then 1?
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
During an experiment, a spinner landed on red 6 times. If the resulting experimental probability of the spinner landing on red is StartFraction 1 over 8 EndFraction, how many trials were performed?
Given, The probability of getting red, P(R) = 1/8 Red occurs by the spinner= 6 times Let, the total number of trials = N Therefore, for the experimental probability the total number of trials performed can be calculated by the following equation: P(R) = (Red occurs by the spinner)/(Total number of trials) Or, 1/8 = 6/N Or, N = 6 × 8 Or, N = 48 Final Answer: A spinner landed on red 6 times. If the resulting experimental probability of the spinner landing on red is StartFraction 1 over 8 EndFraction, then 48 trials were performed.
What is the probability of spinning a 2 on a 1-6 spinner if I spin it 60 times?
The probability of getting a 2 is 1 - (1/6)60 = 1 - 2.05*10-47
If you spin the spinner 600 times how many times would you expect it to land on green?
Well, if the spinner has equal sections, and green is one of them, then statistically speaking, you would expect it to land on green about 100 times out of 600 spins. But hey, life's full of surprises, so don't bet your retirement savings on it!
A five color spinner with equal sections of red blue green yellow and orange is spun What is the probability of getting no reds in six spins?
If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.
If Emilio spins a 1-8 spinner 10 times and on his first 3 spins the spinner lands on 8 what is the experimental probability that Emilio will spin a 10 on his fourth spin?
I'm assuming that a "1-8 spinner" is similar to an eight-sided die, so the probability of spinning a 10 is zero. When throwing dice, or flipping a coin, etc., each outcome is independent. That is, it's not influenced by the previous outcome(s). So if you get three 8s in a row then the probability of getting an 8 on the fourth throw remains at 1/8. The probability of an 8 on each and every throw is always 1/8.
What is the probability that you will spin a 4 and roll a 4?
Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60
The spinner is divided into 12 equal parts if you spin the spinner 100 times how many times do you expect the spinner to stop on a number less than 10?
∙It will be spun on a number less than 10 in 75 times if you spin it 100 times.Explanation:Let x be the random variable, x = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.The probability for any outcome is P(x) = 1/12. It is a flat probability distribution.The probability that when you spin the spinner the outcome is a number greater than10 is:P(10 ≤ x ≤ 12) = P(x = 10) + P(x = 11) + P(x = 12 ) = 3/12 = 1/4The probability of the complement event (that the outcome is a number smaller than 10) is: P(x < 10) = 1 - 1/4 = 3/4.So the expected number of times the spinner outcome will be a number smaller than 10 is:P(No. outcomes x
How likely is it for an event to happen written as a percentage?
100 times its probability.100 times its probability.100 times its probability.100 times its probability.
If you spin this spinner 36 times how many times would you expect it to land on 2?
The answer depends on the number of sides on the spinner and how they are numbered.
