Well, honey, in an 8-bit register, you can store a total of 256 different binary values. That's because each bit can be either a 0 or a 1, giving you 2 options per bit. And when you have 8 bits, you just multiply 2 by itself 8 times to get 256. Math doesn't lie, darling.
Answer: 2The values are 0 or 1.
With 6 binary digits, you have 26 different possibilities. This is because there are two possibilities for each digit, and each digit is independent of the other digits - so you just multiply the possibilities for each digit together.
The binary system uses two digits, zero and one.
56 in binary is 111000. Unlike the decimal number system where we use the digits.
Binary form has 2 sections,Ternary form has 3 sections.
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
Answer: 2The values are 0 or 1.
Answer: 2The values are 0 or 1.
64 or 123
65,536
It can have 0 to 1 It can have 0 to 1
4 these are 00,01,10 and 11...
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...
There are 14 Regiters in the computer where data is stored which is currently being process
0 o 1
Texas is too big, but you can fit in a Ohio, Maryland, and part of West Virginia. But seriously though...I am assuming that you mean "how many unique combinations of 1's and 0's can be stored in a 16 bit register." The answer is given as 2 (the number of different possibilities per digit) raised to the power of 16. The answer is 65536, made up of 0 through 65535. An 8 bit register can represent 256 different values, 0 through 255.
Infinite (and binary).