The problem of finding the number of ways to write a positive integer as the sum of distinct positive integers is a classic combinatorial problem known as "partitioning." In this case, we are looking for the number of ways to partition 15 into 4 distinct parts. This can be calculated using a formula derived from Euler, which involves finding the number of partitions of the number into exactly 4 parts and subtracting the number of partitions of the number into 1, 2, or 3 parts. The result in this case is 9.
I assume you mean "stored". In each case, a total of 2 to the power 13 different numbers can be stored.
20 There can be two answers to this: I'll assume this is what you meant-> let's say you mean like pairing the numbers 1-5 with the numbers 6-9. 5*4=20
I assume you mean "six numbers" rather than "sox numbers". If the numbers are all distinct (i.e none of them are in the set of thirty numbers more than once), then there are 30!/(24!6!) ways of choosing six numbers, where "!" is the factorial of that number.
I assume your 4 numbers are 5,10,15 and 20. If you add them and divide by the amount of numbers, you get 5+10+15+20, which is 50, divided by 4 which is 12.5
I assume you mean the sum of the digits.If the first digit is 1, the other two digits have to sum 10. There are 9 different possibilities for this, from 1 + 9 to 9 + 1.If the first digit is 2, the other two digits have to sum 9. There are 10 different possibilities for this, 0 + 9 to 9 + 0.Adding it all up, it seems there are 19 such numbers.
I assume you mean the first three "counting" (ordinal) numbers, which are 1, 2, and 3. The sum is therefore 1 + 4 + 9 = 14.
41 & 39 = 1599. (40 x 40 = 1600 but I assume you meant different numbers)
We'll assume that you only want to talk about whole numbers.The smallest 9-digit number is 100,000,000. The largest one is 999,999,999.They represent (all of the counting numbers up to 999,999,999) minus (the first 99,999,999).That leaves 900,000,000 numbers.
I assume you mean "stored". In each case, a total of 2 to the power 13 different numbers can be stored.
We'll assume that you only want to talk about whole numbers.The smallest 7-digit number is 1,000,000. The largest one is 9,999,999.They represent (all of the counting numbers up to 9,999,999) minus (the first 999,999).That leaves 9,000,000 numbers.
Months have different numbers of days. If we assume sort-of-average months of 30 days, you have to multiply all of the following numbers:2 (the number of months) 30 (days per month)24 (hours per day)60 (minutes per hour)Months have different numbers of days. If we assume sort-of-average months of 30 days, you have to multiply all of the following numbers:2 (the number of months)30 (days per month)24 (hours per day)60 (minutes per hour)Months have different numbers of days. If we assume sort-of-average months of 30 days, you have to multiply all of the following numbers:2 (the number of months)30 (days per month)24 (hours per day)60 (minutes per hour)Months have different numbers of days. If we assume sort-of-average months of 30 days, you have to multiply all of the following numbers:2 (the number of months)30 (days per month)24 (hours per day)60 (minutes per hour)
20 There can be two answers to this: I'll assume this is what you meant-> let's say you mean like pairing the numbers 1-5 with the numbers 6-9. 5*4=20
Let's assume for a moment we're not thinking about negative numbers. Only counting numbers from 0-49, there is the same number even as odd so the answer is no. If you didn't include 0, then the answer would be yes. If you do include negative numbers, then there are an infinite number of both odd and even numbers. In this case it doesn't seem to make sense to say there are more odd numbers than even numbers so the answer is no. In short: No. Yes if it's only 1-49.
He wore number 49.
We'll assume that you only want to talk about whole numbers.The smallest 7-digit number is 1,000,000. The largest one is 9,999,999.They represent (all of the counting numbers up to 9,999,999) minus (the first 999,999).That leaves 9,000,000 numbers
2,3,5, and 7. i assume your question was "if four numbers sum up to 17, what are the numbers?"
We have to assume that you're talking about whole numbers. The sum is 5,050 .