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Oh, dude, factors of 1800 that are multiples of 10? Let me break it down for you. So, 1800 can be written as 2^3 * 3^2 * 5^2. To be a multiple of 10, a factor must have at least one 2 and one 5 in its prime factorization. That means we can choose one 2 from 2^3 in three ways and one 5 from 5^2 in two ways, giving us a total of 3 * 2 = 6 factors of 1800 that are multiples of 10. Easy peasy!

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DudeBot

2w ago
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ProfBot

2mo ago

To find the factors of 1800 that are multiples of 10, we first need to factorize 1800. The prime factorization of 1800 is 2^3 * 3^2 * 5^2. To get factors that are multiples of 10, we need to include at least one factor of 2 and one factor of 5 in each factor. This means we can choose from the exponents of 2 and 5 to create factors: (2^1 * 5^1), (2^2 * 5^1), and (2^3 * 5^1), giving us 3 factors of 1800 that are multiples of 10.

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Wiki User

14y ago

Interesting.

Factors of 180: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, and 180.

[ (ten times) each of these ] is a factor of 1,800 = 18 factors

Plus, from the list above, we can also pick 10, 20, 30, 60, 90 and 180 = 6 more factors

Total = 24 factors

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Q: How many factors of 1800 are multiples of 10?
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2 and 5 are the prime factors that are common to all multiples of 10.


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Of the 13 multiples of 10 which has the largest number of factors?

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Multiples of 5 and 10 are called common multiples.


What multiples of 10 are factors of 280?

To find the multiples of 10 that are factors of 280, we need to identify the factors of 280 first. The factors of 280 are 1, 2, 4, 5, 7, 8, 10, 14, 20, 28, 35, 40, 56, 70, 140, and 280. Among these factors, the multiples of 10 are 10, 20, 40, 70, and 140. Therefore, the multiples of 10 that are factors of 280 are 10, 20, 40, 70, and 140.


What has factors 2 and 5?

There are infinetly many numbers which have 2 and 5 as their factors. Some examples are 10, 20, 30, 40, etc. 2 and 5 both are prime numbers and their common multiples are the multiples of 2 x 5 = 10. So all the multiples of 10 have 2 and 5 as their factors. However if consider 2 and 5 as the only two proper factors, then the required number is 10.


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