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Oh, dude, factors of 1800 that are multiples of 10? Let me break it down for you. So, 1800 can be written as 2^3 * 3^2 * 5^2. To be a multiple of 10, a factor must have at least one 2 and one 5 in its prime factorization. That means we can choose one 2 from 2^3 in three ways and one 5 from 5^2 in two ways, giving us a total of 3 * 2 = 6 factors of 1800 that are multiples of 10. Easy peasy!
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MaxineTo find the factors of 1800 that are multiples of 10, we first need to factorize 1800. The prime factorization of 1800 is 2^3 * 3^2 * 5^2. To get factors that are multiples of 10, we need to include at least one factor of 2 and one factor of 5 in each factor. This means we can choose from the exponents of 2 and 5 to create factors: (2^1 * 5^1), (2^2 * 5^1), and (2^3 * 5^1), giving us 3 factors of 1800 that are multiples of 10.
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What numbers have 2 and 5 as factors?
Multiples of 10.
How many numbers between 1 and 100 (inclusive) are divisible by 3 or 10?
33 multiples of 3 10 multiples of 10 -3 multiples of both 40 total
What is a multiple of 10 and a factor of 45?
If a multiple of 10 were a factor of 45, then both '10' and the multiple would be factors of 45. Since 10 is not a factor of 45, there is no such number.There are no multiples of 10 that are factors of 45.
Why do numbers ending in 0 have factors of 2 and 5?
Numbers ending in zero are all multiples of 10, and therefore also are multiples of 2 and 5.
What is 9x180?
1620 The easiest way to do this in your head is multiply 180 by 10 i.e. you add a "0" on the end so 1800, and then subtract 180 to give you 9 multiples of 180: 1800-180 = 1620
