Oh, dude, factors of 1800 that are multiples of 10? Let me break it down for you. So, 1800 can be written as 2^3 * 3^2 * 5^2. To be a multiple of 10, a factor must have at least one 2 and one 5 in its prime factorization. That means we can choose one 2 from 2^3 in three ways and one 5 from 5^2 in two ways, giving us a total of 3 * 2 = 6 factors of 1800 that are multiples of 10. Easy peasy!
To find the factors of 1800 that are multiples of 10, we first need to factorize 1800. The prime factorization of 1800 is 2^3 * 3^2 * 5^2. To get factors that are multiples of 10, we need to include at least one factor of 2 and one factor of 5 in each factor. This means we can choose from the exponents of 2 and 5 to create factors: (2^1 * 5^1), (2^2 * 5^1), and (2^3 * 5^1), giving us 3 factors of 1800 that are multiples of 10.
Multiples of 10.
If a multiple of 10 were a factor of 45, then both '10' and the multiple would be factors of 45. Since 10 is not a factor of 45, there is no such number.There are no multiples of 10 that are factors of 45.
33 multiples of 3 10 multiples of 10 -3 multiples of both 40 total
Numbers ending in zero are all multiples of 10, and therefore also are multiples of 2 and 5.
1620 The easiest way to do this in your head is multiply 180 by 10 i.e. you add a "0" on the end so 1800, and then subtract 180 to give you 9 multiples of 180: 1800-180 = 1620
2 and 5 are the prime factors that are common to all multiples of 10.
No.
This is a nonsensical question. There are more than 13 multiples of 10 - in fact there are an infinite number. And there are multiples of 10 which have an infinite number of factors - so there cannot be a "largest" number of factors.
Multiples of 5 and 10 are called common multiples.
To find the multiples of 10 that are factors of 280, we need to identify the factors of 280 first. The factors of 280 are 1, 2, 4, 5, 7, 8, 10, 14, 20, 28, 35, 40, 56, 70, 140, and 280. Among these factors, the multiples of 10 are 10, 20, 40, 70, and 140. Therefore, the multiples of 10 that are factors of 280 are 10, 20, 40, 70, and 140.
There are infinetly many numbers which have 2 and 5 as their factors. Some examples are 10, 20, 30, 40, etc. 2 and 5 both are prime numbers and their common multiples are the multiples of 2 x 5 = 10. So all the multiples of 10 have 2 and 5 as their factors. However if consider 2 and 5 as the only two proper factors, then the required number is 10.
Numbers which are the factors of thirty and multiples of five are 5, 10, 15 and 30.
5, 10, and 20 are all multiples of 5 and factors of 20.
No. A factor is a number or algebraic expression by which another is exactly divisible. A multiple is a number that can be divided by another number without a remainder. Factors go into numbers, numbers go into multiples.
Oh, dude, let me break it down for you. So, the factors of 100 are 1, 2, 4, 5, 10, 20, 25, 50, and 100. Out of these, the multiples of 5 are 5, 10, 20, 25, 50, and 100. That's like 6 factors of 100 that are multiples of 5. Easy peasy, lemon squeezy!
Multiples of 10.
Factors of 10: 1, 10, 2, 5 Multiples of 5: 5, 10, 15, etc. From this, we see that 5 and 10 are factors of 10 and multiples of 5. Therefore, there are two numbers that are factors of 10 but not 5. They are: 1 and 2