Oh, dude, factors of 1800 that are multiples of 10? Let me break it down for you. So, 1800 can be written as 2^3 * 3^2 * 5^2. To be a multiple of 10, a factor must have at least one 2 and one 5 in its prime factorization. That means we can choose one 2 from 2^3 in three ways and one 5 from 5^2 in two ways, giving us a total of 3 * 2 = 6 factors of 1800 that are multiples of 10. Easy peasy!
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To find the factors of 1800 that are multiples of 10, we first need to factorize 1800. The prime factorization of 1800 is 2^3 * 3^2 * 5^2. To get factors that are multiples of 10, we need to include at least one factor of 2 and one factor of 5 in each factor. This means we can choose from the exponents of 2 and 5 to create factors: (2^1 * 5^1), (2^2 * 5^1), and (2^3 * 5^1), giving us 3 factors of 1800 that are multiples of 10.
Interesting.
Factors of 180: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, and 180.
[ (ten times) each of these ] is a factor of 1,800 = 18 factors
Plus, from the list above, we can also pick 10, 20, 30, 60, 90 and 180 = 6 more factors
Total = 24 factors
Multiples of 10.
33 multiples of 3 10 multiples of 10 -3 multiples of both 40 total
If a multiple of 10 were a factor of 45, then both '10' and the multiple would be factors of 45. Since 10 is not a factor of 45, there is no such number.There are no multiples of 10 that are factors of 45.
Numbers ending in zero are all multiples of 10, and therefore also are multiples of 2 and 5.
1620 The easiest way to do this in your head is multiply 180 by 10 i.e. you add a "0" on the end so 1800, and then subtract 180 to give you 9 multiples of 180: 1800-180 = 1620