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x=gallons of 25%

y=gallons of 3.5%

.25x + .035y = .125(50)

y=50-x

using substitution for a system of equations:

.25x + .035(50-x) = 6.25

.25x + 1.75 - .035x = 6.25

.215x = 4.5

x=20.93 gallons of cream

y=29.07 gallons of milk

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Q: How many gallons of cream containing 25 percent butter fat and milk containing 3 and a half percent butter fat must be mixed to obtain 50 gallons of cream containing 12 and a half percent butter fat?
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