DISSOLVE 1.2 Gm OF THYMOL CRYSTALS IN 20mL OF ETHYL ALCOHOL. THEN, BRING TO FINAL VOLUME WITH ETHYL ALCOHOL.
Oh, dude, you'd need a lot of water for that. Like, a crazy amount. To dilute copper chloride solution from 100000 ppm to less than 1 ppm, you'd need to dilute it by a factor of 100000. So, you'd need to add 99999 parts water for every part of the original solution. Good luck with that math!
It means you dilute your sample in a volume that is as great as the one you current sample has. Ex: you dilute 50 ml NaCl-solution in 50 ml MQ-water. The result of this is that the concentration will always be halved, seeing as the volume increases twofold.
to convert ratio to percent just multiply the ratio by 100 (sometimes, see below)e.g. suppose a ratio a:b=4:5, so percent of a will be;4/5×100=80or a=80%The above works if the ratio is comparing something to the total, like if the 4:5 ratio represented "4 out of 5 dentists prefer ___", then 80% of the dentists were favorable to the product.But what if you have 4 apples and 5 oranges and the total fruit is 9, then you do not have 80% apples, you have 4/9 = 44.4 % (a big difference).So it is important to know the context of the ratio, before you can just apply one rule and plug and chug, as one professor used to tell me.One real life example from my work. Everybody wants to see real-life examples. We get 2 different chemical which is used to process printing plates. The chemicals are shipped concentrated, and we dilute with water here before use. One of the chemicals states to dilute at a 1:1 ratio, which means 1 gallon of concentrate to 1 gallon of water (it even clarifies it by stating that this bottle will make 2 gallons of mixed solution). The other chemical states to dilute 3:1 water to concentrate, and states this gallon of water will make 4 gallons.
To make an 8-fold dilution, you would mix 1 part of the substance you want to dilute with 7 parts of the diluent (usually water or buffer solution). This results in a total of 8 parts, with 1 part being the original substance and 7 parts being the diluent. This dilution reduces the concentration of the original substance by a factor of 8.
HELP! HELP! HELP! i need to know this question
A 99% solution of alcohol will self-dilute by absorbing moisture from the atmosphere unless completely sealed.
A solution with the highest concentration of solute will contain the largest volume of solvent in 100mL. This means a dilute solution with a low amount of solute will have the highest volume of solvent remaining.
You have 6 litres of alcohol in 24 litres of water You need to add x litres to make 6 equal to 15% of 30 + x. 6 is 15% of 40, so x = 10
Alcohol is an organic solution (water is a polar solvent).You can dilute it from 100% to any lower percentage with water to dilute its strength.Alcoholic Beverages, for example, range from 5% (beer) to 40% (vodka, rum) in general.
99% is pretty close to 100%, so the mix would be 40% alcohol and 60% ginger ale.
To dilute 500 gallons of a 31% solution to a 15% solution you would add 533.33 gallons of the dilutant. For example, if you have 500 gallons of a 31% saline solution you would add 533.33 gallons of water to create 1033.33 gallons of a 15% saline solution.
A dilute form of ethanol is a solution of ethanol in water. It is commonly referred to as alcohol or ethyl alcohol and is commonly used in various applications such as disinfectants, cleaning solutions, and beverages. The concentration of ethanol in a dilute form can vary, with common percentages like 70% or 90% ethanol.
The dilute solution become a concentrated solution.
There will be movement of water by osmosis from the less-concentrated solution (left) to the more-concentrated solution (right). Water will tend to flow from a more-dilute state to a less-dilute state.
A solution that only contains a small amount of solute, is a dilute or very dilute solution.
To make a 10 percent solution, you would need to dilute the 50 percent solution by adding 4 ml of solvent to 1 ml of the 50 percent solution. This will result in a total volume of 5 ml with a 10 percent concentration.
alcohol percentages are usually volume percentages. .05% means 0.0005 (0.91 x)/(x+y) = 0.0005 0.91 x = 0.0005 x + 0.0005 y 0.9095 x = 0.0005 y y = 1819 x so for every 1 ml of the 91% solution add 1819 ml of water.