four
1. represent every individual digit of given hexadecimal in binary form like this 4---------> 0100 8---------> 1000 7---------> 0111 2. combine the individual binary digits in order to get the binary of given hexadecimal number 487 ------------> 0100 1000 0111 ( required binary number )
I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).
You could first convert it to binary, and then to hexadecimal. Because octal and hexadecimal bases are both powers of two, the conversion between those bases and binary is quite easy. To go from octal to binary, take each digit in the number, and convert it to three binary digits: 5 -> 101 3 -> 011 2 -> 010 4 -> 100 So the binary version of the number is: 101 011 011 010 100 In order to convert to hexadecimal, your number of digits needs to be divisible by four (as 24 = 16). To get that, we need to add a digit, which will be a zero as our leftmost digit: 0101 0110 1101 0100 Now we can convert each of those sets of four binary digits into single hexadecimal digits, giving us our final answer: 9AD8
7 digits
four
4 digits - representing 16 integers.
1. represent every individual digit of given hexadecimal in binary form like this 4---------> 0100 8---------> 1000 7---------> 0111 2. combine the individual binary digits in order to get the binary of given hexadecimal number 487 ------------> 0100 1000 0111 ( required binary number )
10 digits.
To store the hexadecimal number FF, we need to convert it to binary first. FF in hexadecimal is equivalent to 1111 1111 in binary, which requires 8 bits to represent. Each hexadecimal digit corresponds to 4 bits in binary, so two hexadecimal digits (FF) require 8 bits to store.
Each 4-digit string of binary digits is equivalent to 1 single hexadecimal digit.
4 bits equal to half byte.8 bits is one byte.when converting hexadecimal digits to binary, each hexadecimal digits will take 4 binary digits, which means 4 bits.Because one binary digit means one bit having two values [true/false] or [on/off] like that.. [0/1]we can represent one hexadecimal digit as 4 bits like..for [7] as hexadecimal, we can say [0111] in bits.
The number of digits required to store a number in binary is substantially greater than that required in octal and even larger than in hex.
I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).
Hexadecimal colour codes are codes comprising six hexadecimal digits in whichthe first two digits represent the red colour typethe middle two digits represent the green colour typethe last two digits represent the blue colour typeSince two hexadecimal digits give 256 values, the 6 digit code can represent 16,777,216 colours.
Well, honey, in assembly language, you convert binary to hexadecimal by grouping the binary digits into sets of four, then converting each group into its hexadecimal equivalent. You can use bitwise operations like shifting and masking to make the conversion process smoother. Just remember, in the end, hexadecimal is just a fancy way of saying "base 16."
0xc = 1100 Hexadecimal digits use exactly 4 binary digits (bits). The 0x0 to 0xf of hexadecimal map to 0000 to 1111 of binary. Thinking of the hexadecimal digits as decimal numbers, ie 0x0 to 0x9 are 0 to 9 and 0xa to 0xf are 10 to 15, helps with the conversion to binary: 0xc is 12 decimal which is 8 + 4 → 1100 in [4 bit] binary.