Best Answer

9*10*10*10*10 - 8*9*9*9*9

Q: How many integers from 1 to 100000 contain the digit 6 at least once?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

There are 45 integers between 11 and 999999 which consist of only one digit being repeated. There are 831430 integers that contain at least one repeated digit.

Greatest: 989949 Least: 100000

There are 352.

The largest six digit number period is 999999. The largest number meeting your criteria is 998949.

27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797

Related questions

There are twelve instances where the integers from 1 to 200 contain the digit 1 at least twice:-11,101,110,111,121,131,141,151,161,171,181,191.

There are 45 integers between 11 and 999999 which consist of only one digit being repeated. There are 831430 integers that contain at least one repeated digit.

Greatest: 989949 Least: 100000

Positive integers are greater than negative integers. For positive integers: * The integer with more digits is larger. * If two integers have the same length, compare the first digit. If the first digit is the same, compare the second digit, then the third, etc., until you find a difference. In each case, the integer with the larger digit (at the first position where you find a difference) is the larger one.

There are 352.

The largest six digit number period is 999999. The largest number meeting your criteria is 998949.

252

There is a clever but tricky way to solve this. If we have to find the number of 4-digit integers that contains at least one 5, we can also find the number of all the 4-digit integers and the number of integers that do not contain any 5's and subtract it from the first number. This is called complementary counting.So, first of all, we must find the number of 4-digit numbers there are. There are 9000 of them.Now, we find the number of 4-digit integers without 5's. By thinking a little bit, we see the first digit must be from 0~9 excluding 5. That is a total of 9 numbers. This is the same for the next three digits. Therefore, there are 94 = 6561 4-digit numbers without a 5.Finally, we can subtract. 9000 - 6561 = 2439

Assuming the question is about positive integers and there are no leading 0s, the answer is NEVER.

252

27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797

There is only one number and that is 123456.