answersLogoWhite

0


Best Answer

252

User Avatar

FinixPro

Lvl 3
3y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

12y ago

252

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many 3 digit numbers contain the digit 2 at least once?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many three digit numbers contain at least two sevens?

27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797


How many 2-digit numbers contain digit 1?

1


How many 5 digit numbers contain exactly two 7 in them?

There are 6804 such numbers.


When The pages of a book are numbered from 1 to 128 How many page numbers contain the digit 6?

The pages of a book are numbered from 1 to 128. How many page numbers contain the digit 6?


How many three digit numbers contain no 7's?

648


How many two-digit numbers do not contain the number 9?

There are 90 two digit numbers, 10 through 99. There are 18 two digit numbers containing a 9. They are 19, 29, 39, 49, 59, 69, 79, 89, and 90 through 99. Therefore, there are 72 two digit numbers that do not contain a 9.


How many whole numbers from 1 to 100 contain the digit 3 exactly once?

18


How many numbers between 1 and 999999 contain at least one 1?

We are to calculate the number of 1-digit to 6-digit numbers (i.e. numbers less than one million) that have at least one 1. Let's divide this into six cases by the number of digits in the number.For one digit numbers, the only number is 1 - 1 such number.For two digit numbers, we can find the number which do not contain a 1 more easily. There are 8 possible digits for the tens place (0 and 1 are not allowed), and 9 digits for the ones place (1 is not allowed). Thus we have 8 * 9 = 72 which do not work. There are 90 two digit numbers, so 90 - 72 = 18 such numbers.For three digit numbers, we will proceed in the same manner. There are 900 total 3 digit numbers, of which 8 * 9 * 9 = 648 numbers which do not contain a 1. The remaining 900 - 648 = 252 numbers contain at least 1 one - 252.For four digit numbers, continuing in the same manner we have 8 * 9 * 9 * 9 = 5832 which are not good out of the 9000 total. So, 9000 - 5832 = 3168.For five digit numbers, we have 8 * 9 * 9 * 9 * 9 = 52488. The remaining 90000 - 52488 = 37512 are good.For six digit numbers, we have 8 * 9 * 9 * 9 * 9 * 9 = 472392. The reamining 900000 - 472392 = 427608 are good.Finally, adding all of the totals, we have 1 + 18 + 252 + 3168 + 37512 + 427608 = 468,559 numbers between 1 and 999999 which contain at least 1 one.


How many 6 digit numbers contain exactly different 4 digits?

There are 22680 numbers, excluding those with leading 0s.


How many 5 digit numbers have at least one 2 or 3 among their digits?

There are 61328 of them.


How many numbers between 1 and 100 use the digit 6 at least once?

19 of them


How many numbers from 30 to 60 contain the digit 3?

13