To find the total number of integers between 100 and 300 that are divisible by 3, we first determine the smallest and largest integers in this range that are divisible by 3. The smallest integer divisible by 3 is 102, and the largest is 297. To find the total number of integers between 102 and 297 that are divisible by 3, we calculate (297-102)/3 + 1, which equals 66. Therefore, there are 66 integers between 100 and 300 that are divisible by 3.
There are seven of them. They are: 20, 40, 60, 80, 100, 120 and 140.
There are 1000 integers from 1 to 1000. Only the multiples of 30 of these integers are divisible by 30, such as 30, 60, 90, 120, 150, 180, 210, 240, ..., 990. Since the LCM of 16 and 30 is 240, then only 7 integers from 1 to 1,000 are divisible by 30 but not by 16, which are 30, 60, 90, 120, 150, 180, and 210. (Prime factorization: 30 = 2 x 3 x 5 16 = 24 The LCM of 30 and 16 is 24 x 3 x 5 = 240.)
Let three consecutive integers be n, n+1 and n+2. If n is divisible by 3 then n+1 and n+2 cannot be divisible by 3 as these numbers will respectively leave remainders of 1 and 2. If n is not divisible by 3 then it will leave a remainder of 1 or 2. If n leaves a remainder of 1, then n+1 leaves a remainder of 2 and n+2 is therefore divisible by 3. If n leaves a remainder of 2, then n+1 is divisible by 3 and n+2 is not divisible by 3 as it leaves a remainder of 1.
Here is the way to solve this problem. Since the number has to be divisible by 7 and 4 this means that the number has to be divisible by 28. The smallest multiple of 28 is 281 and the largest multiple through 1-100 is 283. the since the one is inclusive you do 3-1+1 which equals 3. 3 integers is the answer.
333 integers.
Between 1 and 2018, 1008 are not divisible by 2.1613 are not divisible by 5.
All integers are divisible by 1.
There are 189.
193 of them are divisible by one (or more) of the given numbers.
All positive integers are divisible by one.
All integers are divisible by one.
500 numbers in the range [1, 1000] are divisible by 2.
Divisible by both? 2 numbers... 45 and 90
All integers are evenly divisible by 1.
5 of them.
All positive integers.