90 ml of dextrose and 4.41 litres of water.
Y= 444.4, x=844.4
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
2.5ml
16 2/3 liters
Let v be the capacity in milliliters of the 75% solution required then (90 - v) is the required capacity of the 84% solution needed. 75/100v + 84/100(90 - v) = 77/100 x 90 75v + 84(90 - v) = 77 x 90 75v + 7560 - 84v = 6930 9v = 7560 - 6930 = 630 v = 70 : therefore (90 - v) = 20 The mixed solution requires 70ml of the 75% solution and 20ml of the 84% solution to create 90ml of 77% solution.
To find a percentage you need to firstly divide the number (120) by 100. 120 / 100 = 1.2 Then you need to times this number by the percent needed (85). 1.2 x 85 = 102 Therefore 85% of 120 is 102.
25
694 mL of glucose solution 0,2 M are needed.
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
300 ml
My calulation says 286ml of 25% and 214ml of 60% 286 x .25= 71.50 214 x .60= 128.40 250 x .20= 50.00 250 x .60= 150.00
150 mL x 40.0 g LiNO3/100 mL solution = 60.g of solute
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
25 mL
144liters
50liters
256 liters
50 liters