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How many mL of a 20 percent solution are needed to prepare 500 mL of a 5 percent solution?
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
How much of a 4 percent solution is needed for a 100mg dose?
2.5ml
A chemist needs 90 milliliters of a 77 percent solution but has only 75 percent and 84 percent solutions available Find how many milliliters of each that should be mixed to get the desired solution?
Let v be the capacity in milliliters of the 75% solution required then (90 - v) is the required capacity of the 84% solution needed. 75/100v + 84/100(90 - v) = 77/100 x 90 75v + 84(90 - v) = 77 x 90 75v + 7560 - 84v = 6930 9v = 7560 - 6930 = 630 v = 70 : therefore (90 - v) = 20 The mixed solution requires 70ml of the 75% solution and 20ml of the 84% solution to create 90ml of 77% solution.
What rate of simple interest is needed for 1000 to double in 3 years?
331/3 percent simple interest will double any amount in 3 years.
How many 90 minute digital recorders needed to record 100 percent of a 5.5 hour meeting?
You would need four recorders. The total time you could potentially record then would be six hours.
How many ml of 50 percent dextrose solution and how many ml of water are needed to prepare 100ml of 15 percent dextrose solution?
30 ml 50% dextrose + 70 ml water
How many ml are needed to prepare 1 liter of 2.5 percent dextrose solution?
25
How many ml of 50 percent dextrose solution are needed to obtain 25 g of dextrose?
25
How many mL of a 20 percent solution are needed to prepare 500 mL of a 5 percent solution?
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
What volume of 24 percent citric acid is needed to prepare eight 3 ounce bottles of 10 percent citric acid solution?
300 ml
How many grams of glucose are needed to prepare 400ml of a 5 percent glucose solution?
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
How many ml of 25percent dextrose and needed to prepare 500 ml of 40percent dextrose if you are to make 40percent dextrose from 25percent dextrose and 60percent dextrose?
My calulation says 286ml of 25% and 214ml of 60% 286 x .25= 71.50 214 x .60= 128.40 250 x .20= 50.00 250 x .60= 150.00
How much solute is needed to prepare 150mL of a 40.0 percent lithium nitrate solution?
150 mL x 40.0 g LiNO3/100 mL solution = 60.g of solute
How many grams of glucose are needed to prepare 400 ml of a 2.0 percent glucose solution?
8.0 g according to my teacher but i dont know the formula
What volume of 12M HCl solution is needed to prepare 250 mL of 0.100M solution?
25 mL
How many moles of NaOH are required to prepare 5.00 L of 0.025 M Solution?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml?
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
