0
How much water must be added to 425 g of formaldehyde to prepare a 40.0 percent by mass solution of formaldehyde?
Wiki User
∙ 10y ago
637.5 g h20. 40%=(425/425+g) and solve.
Wiki User
∙ 10y ago
To calculate the amount of water needed, first determine the mass of formaldehyde in the final solution. Since the solution is 40.0% formaldehyde by mass, the mass of formaldehyde is 40.0% of the final solution mass. Subtract the mass of formaldehyde in 425 g from this value to find the mass of water needed to prepare the solution.
Add your answer:
Earn +20 pts
How much of a 37 percent formaldehyde solution should be put into 900 ml of water to make a 10 percent formaledhyde solution?
To make a 10% formaldehyde solution, we first need to find out how much pure formaldehyde is in the 37% solution. Then, we can set up a proportion to determine how much of the 37% solution must be used. First, calculate the amount of pure formaldehyde in the 37% solution (37% of x = amount of pure formaldehyde). Then, set up the proportion: (amount of pure formaldehyde in 37% solution) / (total volume of 10% solution) = 10%. Solve for the amount of 37% solution needed.
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
Why KI is to be added to prepare to prepare iodine solution?
Potassium iodide (KI) is added to prepare iodine solution because it helps dissolve iodine (I2) in water, increasing its solubility and stability. This results in a more concentrated solution that is easier to work with for various applications, such as in titrations or as an antiseptic.
How many grams of glucose must be added to 525 g of 2.5 percent leg mass glucose solution?
how many grams of glucose must be added to 525g of 2.5 percent leg mass glucose solution?and give the furmela?
How many grams of KMnO4 should be used to prepare 2L of a 5M solution?
To prepare 2L of a 5M solution, you should put in 4.6575grams of KMnO4. It is important to make sure that you add them in that order. K should be added first, then Mn.
How much of a 37 percent formaldehyde solution should be put into 900 ml of water to make a 10 percent formaledhyde solution?
To make a 10% formaldehyde solution, we first need to find out how much pure formaldehyde is in the 37% solution. Then, we can set up a proportion to determine how much of the 37% solution must be used. First, calculate the amount of pure formaldehyde in the 37% solution (37% of x = amount of pure formaldehyde). Then, set up the proportion: (amount of pure formaldehyde in 37% solution) / (total volume of 10% solution) = 10%. Solve for the amount of 37% solution needed.
What color is formaldehyde?
Formaldehyde is a colorless gas at room temperature. In its liquid form, it is also colorless.
How much of a ten percent solution should be added to two cups of twenty percent solution to make a twelve percent solution?
2%
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?
10 liters.
How much water added to convert a 10 percent solution to 02 percent solution?
add 4 parts water per part solution
How much salt must be added to 60kg of a 20 percent solution of salt to increase it to 40 percent solution of salt?
20%
How much water must be added to 12 L of a 40 percent solution of alcohol to obtain a 30 percent solution?
4 litres
How many gallons of 3 percent salt solution must be mixed with 50 gallons of 7 percent salt solution to obtain a 5 percent salt solution?
50 gallons @ 3% must be added.
How much water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution?
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
A 280 mL solution is 20 percent salt How much water should be added to make the solution 14 percent salt?
98 mL
Why KI is to be added to prepare to prepare iodine solution?
Potassium iodide (KI) is added to prepare iodine solution because it helps dissolve iodine (I2) in water, increasing its solubility and stability. This results in a more concentrated solution that is easier to work with for various applications, such as in titrations or as an antiseptic.
