0
8 digits will generate over 40,000 permutations.
Wiki User
∙ 8y ago
Add your answer:
Earn +20 pts
How many four digit numbers can be made using 1-2-3-4?
It is a permutation problem (any number can be used repeatedly), it will become 4 x 4 x 4 x 4 = 256 four digit numbers. If each number can only be used once, then the answer is 4 x 3 x 2 x 1 = 24 four digit numbers.
How many license plate combinations with three letters and two digits?
I suspect that you want permutations rather than combinations. The permutation ABC is different from ACB, but they are both the same combination. There are 26*26*26*10*10 or 1,757,600 possible permutations of 3 letters followed by 2 numbers. But there are ten ways of arranging 3 letters and 2 numbers: eg LLLNN, LNLNL etc. All in all, therefore, 17,576,000 permutations. However, some letters are not used so as to avoid confusion between letters and numbers: eg 0 and O. Also, some sequences are not used because they form (or suggest) inappropriate words.
How many different digit personal identification numbers are possible if no digit can be used twice a. 1000 b. 5040 c. 9000 d. 10000?
The answer depends on how long the PIN string is. With a ten digit string, where a leading zero is permitted, the answer is 3628800.With only 4 digits, and with leading zero permitted, the answer is 5040.
How many gallons of gas is used if you get 23 miles per gallon with 10000 miles used?
If you get 23 mpg, that means that for every gallon of gas, you travel 23 miles. Simply divide the number of miles travelled by the number of miles you travel per gallon of gas. In this case, 10000 miles / 23 mpg = 434.8 gallons.
How many digits are used to write all numbers from 1 - 100?
-99
When we use permutation or combination?
Permutation is when order matters, combination is when order does not matter
Permutation combination?
They are concepts used in probability theory.
How many four digit numbers can be made using 1-2-3-4?
It is a permutation problem (any number can be used repeatedly), it will become 4 x 4 x 4 x 4 = 256 four digit numbers. If each number can only be used once, then the answer is 4 x 3 x 2 x 1 = 24 four digit numbers.
How many 4 digit combinations can be made from the numbers 0 to 9?
If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
Why are combination locks so called when they are in fact permutation locks?
They are called combination locks because that is the general, conventional term used. Trying to call them permutation locks is mixing different areas of usage together and that is not valid.
What is Definition of word permutation?
* substitution: an event in which one thing is substituted for another; * the act of changing the arrangement of a given number of elements * complete change in character or condition; "the permutations...taking place in the physical world"- Henry Miller * act of changing the lineal order of objects in a group
What is Average cost of electroencephalograph?
new: usd$ 10000 - 40000 used/refurbished 750 - 10000
Consider prime numbers between 1 and 10000. Draw a flowchart to display the prime numbers.Write a pseudo code associated with the flowchart in a)?
A) Here's an example of a flowchart and pseudocode that could be used to display the prime numbers between 1 and 10000: Flowchart: START Set up an array of numbers from 1 to 10000 Set an empty array to store the prime numbers Set i = 2, the first prime number For each number in the array, check if it is divisible by i If it is divisible by i, it is not a prime number and move to the next number in the array If it is not divisible by i, it is a prime number and add it to the prime numbers array Increase i by 1 and go back to step 4 Repeat steps 4 through 7 until i is greater than the square root of 10000 Display the prime numbers array END
How many times is the number 9 used between 1 and 1000000?
If we throw 1000000 out of our calculations (this is okay because it doesn't have any nines in it) then we're left with all the numbers with 6 or less digits. There are 10 choices for each digit. If the 100000's digit is 9, then there are 105=10000 ways to choose the remaining digits, so there are 10000 numbers that have 9 in the 100000s place. Similarly, there are 10000 numbers that have 9 in the 10000s place, 10000 numbers with 9 in the 1000s place, and so on. There are 6 different places 9 could be in, so the digit 9 is used 10000*6 or 60000 times. Improved... well your missing a zero in your answer.... the total amount of 9's used should be 600 000 , not 60 000 because already in the hundred thousands digit 9 is being used 100 000 times becasue from 900 000- 999 999, the number nine is being used atleast 100 000 times so already your answer is wrong. And if you did you method corectly, it should be the same for every other digit, which means the answer will be that 9 will appear 600 000 times between 1 and 1 000 000. Correct me if im wrong, but im pretty sure that that is the answer. (sources):http://www.cemc.uwaterloo.ca/contests/past_contests/2008/2008GaussSolution.pdf (question 25)
How many numbers are used in a binnary code?
1
What numbers can you use to get 42?
There are many possible options. These depend on whether or not numbers can be used many tomes, and also on what operators are allowed.
When the solid acid dissolves to form ions how many moles of H plus ions are produced for every mole of acid used?
10000
