60
independent
Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60
9
For any event, the complementary event is all of the other possible outcomes. For an event (Rolling a number cube) " Rolling an odd number " The complementary event is " Rolling an even number "
Probability of a = number of a/total number = 3/8
2
independent
-2
Six times the number of different outcomes on the spinner.
Because the number cube is not sentient enough to know the result of the spinner and modify its own outcome accordingly. And conversely, the outcome of the spinner is not affected by the roll of the cube.
To calculate the probability of spinning a multiple of 3 on a spinner labeled 1 through 10, we first determine the total number of favorable outcomes. The multiples of 3 between 1 and 10 are 3, 6, and 9. Therefore, there are 3 favorable outcomes. Since there are a total of 10 equally likely outcomes on the spinner, the probability of spinning a multiple of 3 is 3/10 or 0.3.
Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60
9
There are 3 possible outcomes for each spin of the spinner. To find the total number of possible outcomes after spinning it four times, you would multiply the number of outcomes for each spin (3) by itself four times (3^4), resulting in 81 possible outcomes.
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
To determine the probability of spinning a prime number on a spinner, we first need to identify the prime numbers on the spinner. Prime numbers are integers greater than 1 that are only divisible by 1 and themselves. Common prime numbers less than 10 include 2, 3, 5, and 7. If the spinner has numbers 1 through 10, there are 4 prime numbers out of 10 possible outcomes. Therefore, the probability of spinning a prime number on the spinner is 4/10 or 40%.
To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.