63=6*6*6=216
6 outcomes each roll, 3 rolls. 6*6*6 = 216.
6 outcomes for each die and so 6x6x6 outcomes for all three
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
4? i donot know what u mean
There are six possible outcomes. Assuming the probability of each outcome is the same (dice has no defects), then you are likely to roll the number two, 100/6=50/3=16.67 times.
6 x 6 x 6 = 216
When rolling 3 six-sided dice, each die has 6 possible outcomes. Therefore, the total number of combinations can be calculated by multiplying the number of outcomes for each die: (6 \times 6 \times 6 = 216). Thus, there are 216 different combinations possible when rolling 3 dice.
There are 6 outcomes with one roll and 6^2 with two and 6^3 with three. So the answer is 216.
Total number of outcomes = 6*6 = 36 Number of favourable outcomes: 3 [1,3], [2,2] and [3,1] So prob = 3/36 = 1/12
6 outcomes each roll, 3 rolls. 6*6*6 = 216.
3/6
6 outcomes for each die and so 6x6x6 outcomes for all three
Depends if the dice is bias then you an not have an answer if it is fair then you times 6 by 3 which = 18 so if you want three different outcomes then 3/18 which is simplified to 1/6 of a chance!
There are 15 ways to make 7 using 3 dice.
Depends if the dice is bias then you an not have an answer if it is fair then you times 6 by 3 which = 18 so if you want three different outcomes then 3/18 which is simplified to 1/6 of a chance!
3
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%