6 outcomes each roll, 3 rolls. 6*6*6 = 216.
6 outcomes for each die and so 6x6x6 outcomes for all three
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
There are six possible outcomes. Assuming the probability of each outcome is the same (dice has no defects), then you are likely to roll the number two, 100/6=50/3=16.67 times.
4? i donot know what u mean
6 x 6 x 6 = 216
There are 6 outcomes with one roll and 6^2 with two and 6^3 with three. So the answer is 216.
Total number of outcomes = 6*6 = 36 Number of favourable outcomes: 3 [1,3], [2,2] and [3,1] So prob = 3/36 = 1/12
6 outcomes each roll, 3 rolls. 6*6*6 = 216.
6 outcomes for each die and so 6x6x6 outcomes for all three
3/6
Depends if the dice is bias then you an not have an answer if it is fair then you times 6 by 3 which = 18 so if you want three different outcomes then 3/18 which is simplified to 1/6 of a chance!
Depends if the dice is bias then you an not have an answer if it is fair then you times 6 by 3 which = 18 so if you want three different outcomes then 3/18 which is simplified to 1/6 of a chance!
There are 15 ways to make 7 using 3 dice.
3
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
We need to find two things. FIrst we need to know how many ways there are to roll a 3 and second we need to look at how many total events (the sample space) there are. So we could get a 3 with a 1 and 2 or a 2 and 1. Since we are rolling 2 dice we can't have 3 and 0 since we cant roll a 0. So there are 2 ways to get 3. Now Each die has 6 different outcomes when we roll it so using the multiplication law, we hae 36 possible outcomes. Of these 2 give us a sum of 3 so that is 2/36 or 1/18