63=6*6*6=216
6 outcomes each roll, 3 rolls. 6*6*6 = 216.
6 outcomes for each die and so 6x6x6 outcomes for all three
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
There are six possible outcomes. Assuming the probability of each outcome is the same (dice has no defects), then you are likely to roll the number two, 100/6=50/3=16.67 times.
4? i donot know what u mean
6 x 6 x 6 = 216
There are 6 outcomes with one roll and 6^2 with two and 6^3 with three. So the answer is 216.
6 outcomes each roll, 3 rolls. 6*6*6 = 216.
Total number of outcomes = 6*6 = 36 Number of favourable outcomes: 3 [1,3], [2,2] and [3,1] So prob = 3/36 = 1/12
3/6
6 outcomes for each die and so 6x6x6 outcomes for all three
Depends if the dice is bias then you an not have an answer if it is fair then you times 6 by 3 which = 18 so if you want three different outcomes then 3/18 which is simplified to 1/6 of a chance!
Depends if the dice is bias then you an not have an answer if it is fair then you times 6 by 3 which = 18 so if you want three different outcomes then 3/18 which is simplified to 1/6 of a chance!
There are 15 ways to make 7 using 3 dice.
3
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
We need to find two things. FIrst we need to know how many ways there are to roll a 3 and second we need to look at how many total events (the sample space) there are. So we could get a 3 with a 1 and 2 or a 2 and 1. Since we are rolling 2 dice we can't have 3 and 0 since we cant roll a 0. So there are 2 ways to get 3. Now Each die has 6 different outcomes when we roll it so using the multiplication law, we hae 36 possible outcomes. Of these 2 give us a sum of 3 so that is 2/36 or 1/18