6 outcomes for each die and so 6x6x6 outcomes for all three
C(8,3) = 56
The number of outcomes depends on what the experiment is! If the variable of interest is the size, there are just three outcomes. If the variable of interest is price, then there is not enough information to determine the possible outcomes.
There are eight (8).
9, you just have to multiply for problems like this
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
A baccarat at a casino is a gambling card game that is played between the player and the banker. There are only three possible outcomes, it's either a tie or win for either the player or banker.
In physics, energy can have three possible outcomes: it can be transferred, transformed, or conserved.
There are 23 = 8 possible outcomes.
Six.
With considerable difficulty since there are a lot more than 3 possible outcomes.
Three possible outcomes:WinLooseDraw
THREE
18 outcomes
Number of useful outcomes over number of possible outcomes and simplify it if you can. Imagine you want an even number and you roll a die. There are 6 possible outcomes and three of them are useful outcomes (outcomes we want). 3 6 Simplify it and you get 1 2
Four outcomes, three combinations.
C(8,3) = 56
when you toss a coin three times, the total number of possible outcomes is