Q: How many positive integers each have one less digit than their squares?

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900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.

The set of positive integers is {1,2,3,4,5,...}. When referring to numbers, distinct simply means different from each other e.g. 2,6,7 and 9 are distinct positive integers but 2,6,6 and 9 are not distinct since two of them are equal.

There are 8*8 = 64 such numbers.

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This may or may not be true. The set of "counting numbers" may either be defined as all positive integers (1, 2, 3, 4...) or as all non-negative integers (0, 1, 2, 3, 4...). Similarly, the set of "whole numbers" may be defined as all positive integers, all non-negative integers, or as all integers (...-3, -2, -1, 0, 1, 2, 3...). It all depends on the definition given for each term.

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Positive integers are greater than negative integers. For positive integers: * The integer with more digits is larger. * If two integers have the same length, compare the first digit. If the first digit is the same, compare the second digit, then the third, etc., until you find a difference. In each case, the integer with the larger digit (at the first position where you find a difference) is the larger one.

900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.

They are both evenThey each have 2 digitsFor both numbers the second digit is twice the first digitThey are both positive integers

Positive and negative integers are opposite each other.

If both integers are positive or both negative then the quotient is positive. If they are one of each then the quotient is negative.

The set of positive integers is {1,2,3,4,5,...}. When referring to numbers, distinct simply means different from each other e.g. 2,6,7 and 9 are distinct positive integers but 2,6,6 and 9 are not distinct since two of them are equal.

9876543120

There are 8*8 = 64 such numbers.

Assuming positive integers, and no leading zeros, the range of five digit numbers is 10000 to 99999. The ones that end in zero can be found by taking the four digit numbers: 1000 to 9999 and multiplying each by ten. {1000,1001, 1002, ...9999}, multiplied by ten is {10000,10010,10020,....99990}. There are 9000 of them.

Any 2 digit integers are rational numbers because all integers or whole numbers are rational numbers.

Let me first re-phrase your question: What is the number of (positive) integers less than 10000 (5 digits) and greater than 999 (3 digits)? The greatest 4 digit integer would be 9999. The greatest 3 digit integer would be 999. Let's do some subtraction: 9999 - 999 = 9000 This works because as we count up from 999, each positive integer encountered satisfies your requirements until reaching 10000.

what is least positive integer that is divisible by each of the integers 1 through 7 inclusive ? a 420 b 840 c 1260 d 2520 e 5o40