Decide what symbols you want to allow. For example: 26 uppercase letters + 26 lowercase letters + 10 digits = 62. Or less, if you don't want to distinguish uppercase and lowercase; or more, if you want to allow certain special symbols such as spaces, hyphens, etc. Raise this number to the sixth power, if you use 6 characters.
it is 26
26 lower case letters + 26 uppercase letters + 10 numerals = 62 characters 624 = 14776336
24
There are 26 characters in the English alphabet, plus 10 numerals. The total amount of combinations for 2 alphanumeric chars is given by (26+10)²=1296 If you also include capital letters then the result is (26+26+10)²=3844 Only letters gives 26²=676
6 letters minus your 2 unchanging letters leaves you with 4 letters of any combination of 26 possible characters each. That is 26^4 26 to the 4th. 456976 different combinations. If you understand permutations I used the simple repeatable permutations formula x^n.
it is 26
There are 36 possible characters (26 letters + 10 numbers) that can be used in each position of the 11-digit combination. Therefore, the total number of possible combinations is 36^11, which is approximately 7.52 x 10^17. This means there are over 750 quadrillion possible 11-digit combinations of letters A-Z and numbers 0-9 when combined.
26 lower case letters + 26 uppercase letters + 10 numerals = 62 characters 624 = 14776336
im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.
24
There are 26 characters in the English alphabet, plus 10 numerals. The total amount of combinations for 2 alphanumeric chars is given by (26+10)²=1296 If you also include capital letters then the result is (26+26+10)²=3844 Only letters gives 26²=676
3,124,550 possible combinations
With a Latin alphabet of 26 letters and the 10 digits 0...9, and allowing for repeats, you get: 36^4 = 36 × 36 × 36 × 36 = 1,679,616 combinations. If you were to include both lower and upper case characters, the number of possible combinations goes up (due to 26 lower case letters + 26 upper case letters + 10 digits = 62 characters to choose from): 62^4 = 14,776,336.
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
10
To calculate the total number of possible combinations for a license plate using 3 letters and 3 numbers, we need to multiply the number of options for each character position. For letters, there are 26 options (A-Z), and for numbers, there are 10 options (0-9). Therefore, the total number of combinations can be calculated as 26 (letters) * 26 (letters) * 26 (letters) * 10 (numbers) * 10 (numbers) * 10 (numbers) = 17,576,000 possible combinations.
Say you have the letters A,B, and C. Here are all the possible combinations. * ABC * ACB * BAC * BCA * CAB * CBA So, 6 if you don't repeat any of the letters. If you DO repeat letters, then simply take the number of letters you have, (3 for instance), and multiply it to the power of the number of letters you have. So, for 3 letters, the formula would be 33 . Or if you had 4 letters it would be 44 and so on.