As each cube can land with 1 of 6 faces on top there are 6 × 6 = 36 possible outcomes
If the numbers displayed on the top faces are added together then there are 11 possible outcomes: 2, 3, 4, ..., 11, though they do not all occur with the same frequency:
2 can only occur when both cubes show a 1
3 can occur when one shows a 1 and the other shows a 2
4 can occur when one shows a 1 and the other shows a 3, or they both show a 2
and so on.
The number of ways the sums can occur is:
2 - 1 way
3 - 2 ways
4 - 3 ways
5 - 4 ways
6 - 5 ways
7 - 6 ways
8 - 5 ways
9 - 4 ways
10 - 3 ways
11 - 2 ways
12 - 1 way
1 + 2 + 3 + 4 + 5 + 6 + 5 + 4 + 3 + 2 + 1 = 36 - all the possible outcomes of throwing the two cubes.
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There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)
The outcomes are: heads, tails, tails or tails, heads, tails or tails, tails, heads. You can see that there are 3 possible outcomes with exactly 1 head.
There are sixteen different outcomes. To figure this you multiply the number of possible outcomes for each coin, which is 2 for all of them. So you take 2^4 which comes out to 16.
it would be 2*2*6 which would equal 24