Each coin can land in two ways.
The die has 6 possible outcomes.
So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.
Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
24 possible outcomes.
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
9
There are eight (8).
The possible outcomes areHH, HT, TH and TT.
16
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
24 possible outcomes.
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
There are 48 possible outcomes and I have no intention of listing them all. They are all of the form CCCD where C = H or T, and D takes the numeric values from 1 to 6.
There are 25 or 32 possible outcomes can you get by tossing 5 coins.
There are 23 = 8 possible outcomes.
Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.
As a group, I count four. 3 heads 3 tails 2 heads, 1 tail 2 tails, 1 head
I believe there would be 11 possible outcomes!
If you toss eight coins, there are 256 (28) different outcomes.
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.