If the dividend is a multiple of 8 then there will be no remainders in the quotient otherwise the possible remainders are limitless
8 integer remainders. From 0 to 7 (inclusive).
With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.
The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.
There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.
The possible number of remainders is always one less than the divisor.
8 integer remainders. From 0 to 7 (inclusive).
With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.
The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.
There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.
Walang remainder
The possible number of remainders is always one less than the divisor.
When 9 is used as a divisor, the remainders can range from 0 to 8. This is because the remainder is always less than the divisor. So, if you divide any number by 9, the possible remainders can be 0, 1, 2, 3, 4, 5, 6, 7, or 8.
There are 8 possible remainders - including 0.
Anything less than 8.
Assuming you are dividing an integer... Eleven - the remainder can be: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, or 10.
Say for example you have 16/5.In remainders, the answer would be 3r1. Now you have to divide the remainder by the divisor So for example: 1/5=0.2 Now you have to place the 3 from the answer we got from the remainder in front of the 0.2 answer: 3.2
Both 16 and 8 are divisors of 64, since both can divide 64 without any remainders. 64/16=4 and 64/8=8.