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If the dividend is a multiple of 8 then there will be no remainders in the quotient otherwise the possible remainders are limitless

Q: How many possible remainders are there when 8 is the divisor?

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8 integer remainders. From 0 to 7 (inclusive).

With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.

The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.

There are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, 8.

There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.

Related questions

8 integer remainders. From 0 to 7 (inclusive).

With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.

The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.

There are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, 8.

There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.

Walang remainder

The possible number of remainders is always one less than the divisor.

There are 8 possible remainders - including 0.

Anything less than 8.

All non-negative numbers smaller than 9 ie 0, 1, 2, 3, 4, 5, 6, 7 and 8.

Assuming you are dividing an integer... Eleven - the remainder can be: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, or 10.

Both 16 and 8 are divisors of 64, since both can divide 64 without any remainders. 64/16=4 and 64/8=8.