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Let the number be 10x + y, with digits xy. We have (1) x(10x+y) = 96 and (2) x - 1 = y Substitute for y in (1): x(10x+x-1) = 96 Simplify: 11x2 - x = 96 11x2 - x - 96 = 0 Factorising the quadratic... (11x+32)(x-3) = 0 Take x-3 = 0 for an integer solution. Thus x=3 and y=2 The number is 32.

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Q: The product of a two-digit number and its tens digit is 96 Find the number if the units digit is one less than tens digit?
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