Six
Make an equilateral triangle(all same sides) with 3 lines and put the 4th on right through the middle and you have 2 right angle triangles.
Three triangles
35. To check this, you need to check every possible type of triangle, and then consider that there are 5 of this type (or in one case, 10), and add everything up.
yes
I get 9 triangle with fewer than 9 lines. Draw a square: ABCD (4 lines) Draw the diagonals AC, BD (2 lines) which meet at X in the centre. On a separate part of the page, draw triangle PQR (3 lines). That is 4 + 2 + 3 = 9 lines. The triangles are: ABC, BCD, CDA, DAB, AXB, BXC, CXD, DXA, and PQR 9 triangles with 9 lines. Could have done 13 triangles with 7 lines by drawing a line from A to BC.
Make an equilateral triangle(all same sides) with 3 lines and put the 4th on right through the middle and you have 2 right angle triangles.
a triangle where all three sides and all three angles are the same.
An equilateral triangle means a triangle with all three sides with equal dimensions. For drawing an equilateral triangle first you will have to choose a measurement to draw the sides of the triangle. For example, lets take the side to be 4cm. When you draw the base of 4cm you will have to draw the other two sides of 4cm as well. Thus an equilateral triangle is constructed..
Label the triangle ABC. Draw the bisector of angle A to meet BC at D. Then in triangles ABD and ACD, angle ABD = angle ACD (equiangular triangle) angle BAD = angle CAD (AD is angle bisector) so angle ADB = angle ACD (third angle of triangles). Also AD is common. So, by ASA, triangle ABD is congruent to triangle ACD and therefore AB = AC. By drawing the bisector of angle B, it can be shown that AB = BC. Therefore, AB = BC = AC ie the triangle is equilateral.
To create a 6-piece triangle tangram, start with an equilateral triangle and divide it into smaller sections. First, draw a line from each vertex to the midpoint of the opposite side, forming three smaller triangles. Then, bisect each of these smaller triangles by drawing a line from the midpoint of one side to the opposite vertex. This method will yield six distinct triangle pieces that can be rearranged into various shapes.
The angle of rotation for a point on a circle to draw an equilateral triangle is 120 degrees, as the triangle's three equal angles divide the circle into three equal 120° arcs.
A regular hexagon can be divided into 6 equilateral triangles by drawing diagonals between opposite vertices, if that helps.
Consider the pentagon ABCDE. By drawing diagonals from B, we get: 1. Triangle ABE 2. Triangle BDE 3. Triangle BCD -Ashwin Hendre
Not only is it possible but it is very easy.
Any triangle can be divided into congruent triangles in infinitely many ways due to the flexibility of triangle geometry and the infinite number of possible points and lines that can be drawn within the triangle. By drawing segments from vertices to points on the opposite sides or by connecting midpoints of sides, one can create various configurations that yield congruent triangles. Additionally, the use of angles, side lengths, and symmetry can further facilitate the creation of congruent divisions. This versatility ensures that there are limitless ways to achieve such partitions.
h=c sin a
The questioner neglected to include the drawing that accompanied the question in his textbook,so we don't know where point 'D' is ? ? ?