Let the number of sides be n and use the formula: 1/2n(n-3) = diagonals
1/2n(n-3) = 27
Multiply both sides by 2 and then form a quadratic equation:
n2-3n-54 = 0
Solving the above quadratic equation works out as:
n = -6 or n = 9 it must be the latter because the sides can't be negative
Therefore the polygon has 9 sides.
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No more than 27.
It has 27 diagonals
A polygon with 27 sides is called a heptacosagon. The name is derived from the Greek words "hepta" meaning seven and "cosi" meaning twenty. The heptacosagon has 27 vertices and 27 angles, with the sum of its interior angles equal to 4050 degrees.
A 27-sided shape is called a heptacosagon. The prefix "hepta-" denotes the number 7, and the suffix "-gon" signifies a polygon with that many sides. Therefore, a 27-sided polygon is specifically referred to as a heptacosagon in geometry.
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 4500 Hence n - 2 = 4500/180 = 25 and then n = 25 + 2 = 27.