Let the number of sides be n and use the formula: 1/2n(n-3) = diagonals
1/2n(n-3) = 27
Multiply both sides by 2 and then form a quadratic equation:
n2-3n-54 = 0
Solving the above quadratic equation works out as:
n = -6 or n = 9 it must be the latter because the sides can't be negative
Therefore the polygon has 9 sides.
A polygon with 27 sides would be called an icosakaiheptagon.
No more than 27.
It has 27 diagonals
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 4500 Hence n - 2 = 4500/180 = 25 and then n = 25 + 2 = 27.
A 27-sided polygon would be called an icosiheptagon.
9 sides because a nonagon has 27 diagonals
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon. So: 0.5*(81-27) = 27 diagonals
It has 9 sides and it can be an regular or a irregular polygon which is called a nonagon Check: 0.5*(81-27) = 27 diagonals
A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
It depends. It doesn't have to always be the same shape. So it can be 0, it can be 1, as long as it has straight lines and is a closed figure, it's a polygon. * * * * * What? A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
The formula used to find the number of diagonals in a polygon is n(n-3)/2. 30 x 27/2 = 810/2 = 405 diagonals.
For an n-sided polygon, the number of diagonals is 1+2+3+....+(n-4)+2(n-3). For a nine-sided polygon, there are 1+2+3+4+5+2(6)=27 diagonals.
A polygon with 27 sides would be called an icosakaiheptagon.
No more than 27.
Assuming the sum refers to that of the interior angles, the polygon has 27 sides.
For a 9 sided polygon it is: 0.5*(92-(3*9)) = 27 diagonals
Let the number of sides be x and use the diagonal formula:- 1/2*(x2-3x) = 27 Multiply both sides by 2: x2-3x = 54 Subtract 54 from both sides: x2-3x -54 = 0 Using the quadratic equation formula gives x a positive value of 9 So the polygon has 9 sides which is a nonagon