Let the number of sides be n and use the formula: 1/2n(n-3) = diagonals
1/2n(n-3) = 27
Multiply both sides by 2 and then form a quadratic equation:
n2-3n-54 = 0
Solving the above quadratic equation works out as:
n = -6 or n = 9 it must be the latter because the sides can't be negative
Therefore the polygon has 9 sides.
No more than 27.
It has 27 diagonals
A polygon with 27 sides is called a heptacosagon. The name is derived from the Greek words "hepta" meaning seven and "cosi" meaning twenty. The heptacosagon has 27 vertices and 27 angles, with the sum of its interior angles equal to 4050 degrees.
A 27-sided shape is called a heptacosagon. The prefix "hepta-" denotes the number 7, and the suffix "-gon" signifies a polygon with that many sides. Therefore, a 27-sided polygon is specifically referred to as a heptacosagon in geometry.
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 4500 Hence n - 2 = 4500/180 = 25 and then n = 25 + 2 = 27.
9 sides because a nonagon has 27 diagonals
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon. So: 0.5*(81-27) = 27 diagonals
It has 9 sides and it can be an regular or a irregular polygon which is called a nonagon Check: 0.5*(81-27) = 27 diagonals
A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
It depends. It doesn't have to always be the same shape. So it can be 0, it can be 1, as long as it has straight lines and is a closed figure, it's a polygon. * * * * * What? A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
In a regular polygon, the formula to calculate the number of diagonals is n(n-3)/2, where n is the number of sides. For a 27-gon, there would be 27(27-3)/2 = 351 diagonals. These diagonals are line segments that connect non-adjacent vertices of the polygon.
The formula used to find the number of diagonals in a polygon is n(n-3)/2. 30 x 27/2 = 810/2 = 405 diagonals.
For an n-sided polygon, the number of diagonals is 1+2+3+....+(n-4)+2(n-3). For a nine-sided polygon, there are 1+2+3+4+5+2(6)=27 diagonals.
No more than 27.
Assuming the sum refers to that of the interior angles, the polygon has 27 sides.
For a 9 sided polygon it is: 0.5*(92-(3*9)) = 27 diagonals
Let the number of sides be x and use the diagonal formula:- 1/2*(x2-3x) = 27 Multiply both sides by 2: x2-3x = 54 Subtract 54 from both sides: x2-3x -54 = 0 Using the quadratic equation formula gives x a positive value of 9 So the polygon has 9 sides which is a nonagon