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Let the number of sides be n and use the formula: 1/2n(n-3) = diagonals

1/2n(n-3) = 27

Multiply both sides by 2 and then form a quadratic equation:

n2-3n-54 = 0

Solving the above quadratic equation works out as:

n = -6 or n = 9 it must be the latter because the sides can't be negative

Therefore the polygon has 9 sides.

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Q: How many sides does a polygon have if it has 27 diagonals?
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How many side are there in a convex polygon having 27 diagonals?

9 sides because a nonagon has 27 diagonals


How many diagonals are in a 9 sided polygon?

The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon. So: 0.5*(81-27) = 27 diagonals


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How many diagonals are in a nine sided figure?

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It depends. It doesn't have to always be the same shape. So it can be 0, it can be 1, as long as it has straight lines and is a closed figure, it's a polygon. * * * * * What? A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.


How many diagonals are there in a regular 27-gon?

In a regular polygon, the formula to calculate the number of diagonals is n(n-3)/2, where n is the number of sides. For a 27-gon, there would be 27(27-3)/2 = 351 diagonals. These diagonals are line segments that connect non-adjacent vertices of the polygon.


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What is the formula for the number of diagonals in a nonagon?

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