Oh, dude, there are 90 three-digit palindromic numbers. You see, a three-digit palindrome has the form "ABA," where A and B can be any digit from 1 to 9. So, you just multiply the possibilities for A and B, which is 9 choices each, and voilà, you get 9 x 10 = 90. Easy peasy, lemon squeezy!
To be a 3 digit palindromic number, it must be of the form aba.I assume that a 3 digit number must be at least 100 (so that 020 for example does not count as a 3 digit number):a can be any of the nine digits 1-9;for each of these b can be any of the ten digits 0-9Thus there are 9 x 10 = 90 three digit palindromic numbers.
a 8-digits palindromic number is a number consisting of a 4-digits number written and then written backward, i.e. 1234 4321 so there are as many palindromic 8-digits numbers as 4-digits numbers so from 1000 to 9999, so there are 8999 palindromic 8 digits number (I assumed that 00011000 is not to be considered as a valid 8 digit number)
Well, honey, there are 18 palindromic numbers between 10 and 200. Palindromic numbers are like your favorite guilty pleasure - they read the same forwards and backwards. So next time you see a palindromic number, give it a little wink and a nod for being symmetrical in all the right places.
21
Well honey, the numbers between 99 and 3000 are inclusive, so you gotta count 'em all. To find out how many three-digit numbers there are, you subtract the first three-digit number (100) from the last three-digit number (999) and add 1, giving you a grand total of 900 three-digit numbers. So, buckle up and start counting, darling!
There are 199 palindromic numbers between 0 and 1000. These include single-digit numbers (0-9), which total 10, and two-digit numbers (11, 22, ..., 99), which add up to 9. Additionally, there are 90 three-digit palindromic numbers, ranging from 101 to 999, that follow the format aba (where a and b are digits). Thus, the total is 10 (single-digit) + 9 (two-digit) + 90 (three-digit) = 109 palindromic numbers.
90
9
There are 900000 of them.
Palindromic numbers are numbers that read the same forwards and backwards. Between 10 and 1,000,000, the palindromic numbers include 11, 22, 33, ..., 99 for two-digit numbers; 101, 111, 121, ..., 999 for three-digit numbers; and 1001, 1111, 1221, ..., 9999 for four-digit numbers. This pattern continues up to six-digit numbers, such as 100001, 101101, and so forth. In total, there are many palindromic numbers within that range, amounting to thousands when considering all possible digits.
To be a 3 digit palindromic number, it must be of the form aba.I assume that a 3 digit number must be at least 100 (so that 020 for example does not count as a 3 digit number):a can be any of the nine digits 1-9;for each of these b can be any of the ten digits 0-9Thus there are 9 x 10 = 90 three digit palindromic numbers.
899100 of them. Only 900 of the 900000 are palindromic.
A palindromic number can have as few as one digit, and as many as infinity. The smallest palindromic number is zero and the largest is '999... to infinity'.
There is: 101,111,121,131,141,151,161,171,181,191 202,212,222,etc... 999 There are 90 palindromic 3 digit numbers
40. Excluding numbers starting with 0.
a 8-digits palindromic number is a number consisting of a 4-digits number written and then written backward, i.e. 1234 4321 so there are as many palindromic 8-digits numbers as 4-digits numbers so from 1000 to 9999, so there are 8999 palindromic 8 digits number (I assumed that 00011000 is not to be considered as a valid 8 digit number)
There are 199 palindromic numbers between 0 and 1000. These include single-digit numbers (0 to 9), two-digit numbers (e.g., 11, 22, ... 99), and three-digit numbers (e.g., 101, 111, ... 999). Each of these categories contributes to the total, with the three-digit palindromes being in the form of ABA, where A and B are digits.