To determine how many times the digit 4 appears in numbers from 1 to 623, we can consider the units, tens, and hundreds place separately. In the units place, the digit 4 appears once in numbers ending in 4 (4, 14, 24, ..., 614). This happens 62 times. In the tens place, the digit 4 appears 10 times in every hundred numbers (40-49, 140-149, ..., 540-549), so it appears 6 times within the range from 1 to 623. In the hundreds place, the digit 4 appears once in every hundred numbers (400-499), occurring 1 time. Therefore, the digit 4 appears a total of 62 + 6 + 1 = 69 times in numbers from 1 to 623.
How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?
With 123 digits you can make 123 one-digit numbers.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
Not sure what a "didget" is. It is possible to make 18 5-digit numbers.
There are 90 two-digit numbers... starting with 10 and ending with 99.
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The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
Count them
How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
There are 900 three-digit whole numbers between 1 and 1000
the right answer is 10 cause there is o,1,2,3,4,5,6,7,8,9 so there 10 numbers in total which have 1 digit
10,000
With 123 digits you can make 123 one-digit numbers.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
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