Well, honey, if you want to arrange 12 books 3 at a time, that's just a fancy way of asking for a permutation. So, you've got 12 choices for the first book, 11 choices for the second book, and 10 choices for the third book. Multiply those together and you get 1,320 ways to arrange those books. Easy peasy lemon squeezy!
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To calculate the number of ways 12 books can be arranged 3 at a time, we use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 12 and r = 3. Plugging these values into the formula, we get 12C3 = 12! / 3!(12-3)! = 12! / 3!9! = (12 x 11 x 10) / (3 x 2 x 1) = 220. Therefore, there are 220 ways to arrange 12 books 3 at a time.
7654321 = 7! = 5,040
Five numbers can be arranged in 5! = 120 ways.
24 ways.
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
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