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im a webkin
-1
In how many ways can fourfour women be selected from the eighteight ​women
There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.
The formula would be: (40!/36!)/4! This gives 2193360/24, or 91,390 unique groups.
(5x4x3)/(3x2x1) = 10
im a webkin
-1
The number of ways is 18C5 = 18!/(5!*13!) = 8,568 ways.
12C3 = 12*11*10/(3*2*1) = 220
In how many ways can fourfour women be selected from the eighteight ​women
They can be selected in 756 ways.
12!/(5!*7!)The number of ways to arrange nitems is n!, where "!" is the factorial function. The number of ways we can arrange the 12 books is therefore 12!. However, we don't really care what order the first 5 books are in, or what order the last 7 books are in, as long as they're the same books. We therefore divide by the number of ways to arrange 5 books and the number of ways to arrange 7 books.
Because he is races
(21 x 20 x 19) / (1 x2 x3) = 1330
one, 3 x 3 = 9
There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.