(8C3 x 9C4)/17C7= (56 x 126)/19448= about 36.3%
Assuming the question is that you have 5 pictures and want to know how many different ways you could put 3 on a wall from left to right: There are 5 choices for the first picture; for each of these there are 4 choices for the second; and for each of these choices there are 3 choices for the third, meaning a total of: 5 x 4 x 3 = 60 ways that 3 pictures can be arranged from 5.
There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520
5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.
-4
35
93
im a webkin
-1
there are 220 combinations of arranging 12 books chosing 3
Choose 3 then 2 then 1; 3*2*1 = 6 ways.
Two books are compulsory, so the student really wants to know how many ways he can pick 3 out of 7. That is 35.
The number is 30C3 = 30!/[3!*(30-3)!] = 30*29*28/(3*2*1) = 4060
12C3 = 12*11*10/(3*2*1) = 220
2300
one, 3 x 3 = 9
8C3 = 8*7*6/(3*2*1) = 56