Answer: 6
There are 3 choices for the first kid, 2 for the remaing kids and then only 1 space left for the kid at the end of the line.
3x2x1=6 ways.
1. 1232. 1323. 2314. 2135. 3216. 312
for the first student in the line there are 10 choices, then for the second 9 choices left, for the third 8 choices left and so on... So it's 10x9x8x7x6x5x4x3x2x1 = 3628800
4*3*2*1 = 24 ways.
There are n! (n factorial) ways that n people can stand in line. So six people can stand in line in: 1*2*3*4*5*6 = 720 different ways
5x4x3x2x1=120
3
25
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
1. 1232. 1323. 2314. 2135. 3216. 312
First in line can be any of the 4, second any of the remaining 3, third one of the other 2, so there are 4 x 3 x 2 ie 24 different ways.
10!, which is pronounced "10 factorial". This is calculated as 1 x 2 x 3 x 4 ... x 10.
for the first student in the line there are 10 choices, then for the second 9 choices left, for the third 8 choices left and so on... So it's 10x9x8x7x6x5x4x3x2x1 = 3628800
line segment, line ab, __ ab
128
There are 5040 ways.
what is the machine for? Many ways to make something for kids but what is the purpose
In a line, in 6 ways. Around a table, in 2 ways.