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How many whole numbers from1 to 100 contain the digit 2 exactly once?
Wiki User
∙ 12y ago
18 and they are:
2 12 20 21 23 24 25 26 27 28 29 32 42 52 62 72 82 92
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∙ 12y ago
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What are 5 odd number whose sum is 50 from1 to 19?
There are no 5 odd numbers whose sum is 50. (The sum of 5 odd numbers is an odd number whereas 50 is an even number.)
What are all the square numbers from1 - 100?
-99
What are the multiples of 3 from1-100?
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99.
Why is zero factorial equal to one?
It is defined to be so, presumably for the sake of convenience. Some people will tell you that it can be proven, but if it could be proven, it would be categorized as a theorem, not a definition. The common notion is that, since n!/n = (n-1)!, we can substitute 1 in for n and we can see that 0! is 1. The problem with this is that, if 0! is not assumed to be 1 (which is an assumption mathematicians do make), this rule will only hold for values of n that are equal to or greater than 2. To see why, let's look at the proof that n!/n = (n-1)!:n!/n = n!/n | reflexive property(n)(n-1)(n-2).../n = n!/n | definition of factorial(n-1)(n-2)... = n!/n | cancelling the common factor of n(n-1)! = n!/n | definition of factorialNotice that, in order for n! to be described as (n)(n-1)(n-2)... and proceed to be rewritten as (n-1)! after the n's cancel, the natural number n had to be greater than some natural number for (n-1) to be a factor in the factorial. This means that n must be at least 2, because if n were 1, (n-1) would not have been a factor of the factorial, and the proof would fail unless we assume that n is at least 2. So now you know that this rule cannot prove that 0! is 1 because 1 cannot be substituted into the rule because, as it stands, the rule is only valid for values of 2 or greater. The rule is valid for values of 1 or greater if it is assumed that 0! is 1, but that is what you are trying to prove.
What are the numbers from1-15 in spanish?
unodostrescuatrocincoseissieteochonuevediezoncedocetrececatorcequince
How many prime numbers from1 to 100?
25 of them.
Are there more prime numbers from1 25 or26 to 50?
There are more in 1 to 25.
How many prime numbers are in 81?
apart from1, 3x3x3x3, so four I suppose
How do you concatinate two strings using recursion?
Well, it will be slow and inefficient: rec_strcpy (char *to, char *from1, char *from2) { . if (*from1) { . . *to = *from1; . . rec_strcpy (to+1, from1+1, from2); . } else if (*from2) { . . *to = *from2; . . rec_strcpy (to+1, from1, from2+1); . } else { . . *to = '\0'; . } }
Number of prime numbers from1 to 100?
Number of Prime Numbers from 1 to 100 is 25. From 1 to 50 it was 15 From 50 to 100 it was 10
How do you concatenate two strings without using strcat?
Example1:sprintf (to, "%s%", from1, from2);Example2:size_t len1= strlen (from1);memcpy (to, from1, len1);strcpy (to+len1, from2);
What are all the prime numbers from1-41?
2 3 5 7 11 13 17 19 23 29 31 37 41.
What are 5 odd number whose sum is 50 from1 to 19?
There are no 5 odd numbers whose sum is 50. (The sum of 5 odd numbers is an odd number whereas 50 is an even number.)
What are 5 odd number whose sum is from1 to 19?
There are many answers: if numbers can be repeated-1)all '1s' and all '3s' 2)4'1s' and so on....
How many 4 number combinations can you make with numbers from1 to 13 with out the numbers repeating?
(13 x 12 x 11 x 10)/(4 x 3 x 2 x 1) = 715 of them
What time do the lakers start there practice?
from1 to 5
