There are 217 numbers. Just look for a pattern. It's very simple, yet it WILL take you time. Trust me, I just had this math problem in my homework today and I got it right at school.
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
There are 999 whole numbers less than 1000. Whole numbers are all the positive integers starting from 1 up to 999. The number 1000 is not included because it is not less than 1000. So, the total count of whole numbers less than 1000 is 999.
The sum of the first 1,000 whole numbers is 499,500.
What is the units digit of the least whole number greater than 1000 whose digits are all different?
If you are being inclusive, 1000 and 900. If not, 990 and 910.
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
Both 10 and 1000 are individual whole numbers.
There are 900 three-digit whole numbers between 1 and 1000
It is 1000*(1000+1)/2 = 500500
There are 999 whole numbers less than 1000. Whole numbers are all the positive integers starting from 1 up to 999. The number 1000 is not included because it is not less than 1000. So, the total count of whole numbers less than 1000 is 999.
1000 numbers. From 19,500 to 20,499 all round to 20,000
The sum of the first 1,000 whole numbers is 499,500.
2000.The smallest four-digit number there can be is 1000. So, add 1000 and 1000 to get 2000, then least sum you can get when adding two four-digit numbers.
90
Zero
1000
8 and 125