There are 217 numbers. Just look for a pattern. It's very simple, yet it WILL take you time. Trust me, I just had this math problem in my homework today and I got it right at school.
217
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
The sum of the first 1,000 whole numbers is 499,500.
Not including -integers or counting 1000, it would be 999. Counting 1000 it would be, well... 1000
What is the units digit of the least whole number greater than 1000 whose digits are all different?
31-32
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
Both 10 and 1000 are individual whole numbers.
There are 900 three-digit whole numbers between 1 and 1000
It is 1000*(1000+1)/2 = 500500
1000 numbers. From 19,500 to 20,499 all round to 20,000
The sum of the first 1,000 whole numbers is 499,500.
2000.The smallest four-digit number there can be is 1000. So, add 1000 and 1000 to get 2000, then least sum you can get when adding two four-digit numbers.
90
Zero
8 and 125
1000
Just successively divide both numbers by the same numbers and make sure they are whole numbers... 305/1000 = 61/200