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What is the sum of the first 1000 integers?
The sum of the first 1,000 integers (whole numbers) is 499,500.
How do you find the arithmetic mean of the first one thousand positive odd numbers?
The sum of all odd numbers, up to the odd number (2n-1) is n^2. So the sum of the first 1000 or 10^3 odd positive numbers is (10^3)^2=10^6 Now divide by 10^3 or 1000 since we have 1000 numbers so we have 10^6/10^3=1000 The mean of the first 1000 positive odd numbers is 1000 If you ask the mean of the odd numbers between, 1 and 1000, that is another problem, since there are 500 of them, the answer would be 500^2/500=500 Think of the mean of the odd numbers between 1 and 10, there are 5 of them and there sum is 25 so the mean is 25/5 or 5 **** in general, the arithmetic mean of the first n odd numbers is n^2/n or n. So that is why the number is 1000.
What is the sum of the first 1000 consecutive odd numbers?
The first odd number is 1 The 1000th odd number is 1000 x 2 - 1 = 1999 Sum = number_of_numbers x (first_number + last_number) ÷ 2 = 1000 x (1 + 1999) ÷ 2 = 1000 x 2000 ÷ 2 = 1000000
What is the sum of the first 500 consecutive odd numbers?
1,000,000 * * * * * The 1st and 500th sum to (2*1-1)+(2*500-1) = 2*501 - 2 = 1000 The 2nd and 499th sum to (2*2-1)+(2*499-1) = 2*501 - 2 = 1000 There are 250 such sums So sum of all 500 odd numbers = 250*1000 = 250,000
What is the sum of the first 50 numbers?
The sum of the first 50 whole numbers is 1,225.
