Your process is going to have a couple of problems.
-- You'll never turn steam into ice by adding heat. That's like trying to
make a 3-ft board fit into a 2-ft space by gluing another piece onto it.
-- Without some pretty fancy pressurization equipment, it's going to be
pretty difficult to make any ice at 10° C.
80 Kgs
for converting cubic meter to ton , density or specific volume is needed. specific volume unite is m3/kg. steam cubic meter/ (cubic meter/kg)= steam (kg ) /1000= tone of steam
First convert 1 lb of water to lb-moles which is 0.055 lb-moles (you'll need this later). This problem can be broken into 3 steps:(1) You need to detemine how much heat is needed to raise room temperature water (68oF) to 212oF. This can be used using the heat capacity of water which at room temperature is 1 Btu/lboF. So the amount of heat needed for this is:Q1 = m*Cp*ΔT= (1 lb)*(1 Btu/lboF)*(212 - 68oF)= 144 Btu(2) Next you need to account for the phase change. The water changes to steam at 212oF. You use the heat of vaporization which you can look up in any Chemistry or Chemical Engineering Handbook. The Hvap that I found is 17493.5 Btu/lb-mole.Q2 = n(lb-moles)*Hvap= (0.055 lb-moles)*(17493.5 Btu/lb-mole)= 972.64 Btu(3) Next you need to find out how much heat is needed to raise the temperature of the steam from 212 to 213oF. You can look up the heat capacity of steam at 212oF to be 0.485 Btu/lboF.Q3 = m*Cp*ΔT= (1 lb)*(0.485 Btu/lboF)*(213-212oF)= 0.485 BtuTo find the total heat needed add Q1+Q2+Q3 (144+972.64+0.485) =1117.12 Btu
It would take 1 ton of water to create 1 ton of steam.
The answer will depend on the units for the temperature.
50 times of steam
Clouds and steam are forms of evaporated water. Water is the main base for evaporation to occur. Bot clouds and steam can condense in a cool temperature, while water can bothe condense and evaporate. So they are not much alike.
rise temperature, increase the insulation. Also, air does not own much mass. It will not condense the steam faster and much.
4.2 × 105 J
It depends on the ship in question. Steam is often used for things other than just propulsion. It is sometime used to heat a ship and to heat hot water. Nuclear and steam vessels run their power on steam.
Some of the heat is used to produce electricity, the rest is waste and put into the environment. Much of the energy of the heat is lost as the steam passes through the turbines, with the heat being converted to mechanical energy, and then to electrical. This accounts for about 35% to 40% of the energy of the heat, cooling it by the removal of that heat. It would be possible for residual heat to be tapped for conversion into electricity, also, but this is not done in most nuclear reactors. Converting it to electricity would get another 10% or so of the heat of the remaining steam, cooling the steam further. The remainder of the heat is waste. It is dumped into the environment, primarily into the air, by using heat exchangers and cooling towers. In this system, the steam is used to heat water, condensing in the process. The water is then used to heat air in the cooling tower. Another way to get rid of waste heat is to use heat exchangers to heat a nearby body of water, such as a lake, the ocean, or a river. This is usually done only in the summer, when the atmosphere is warm and the cooling towers are not efficient enough to do their work.
756.78 degrees Celsius
That is a question that does not have one single answer. For instance, if the pressure of the steam is raised, less steam is needed. As pressure rises, temperature will also rise due to adiabatic work done on the steam. Also, higher temperatures are needed at higher pressures to make sure the steam does not condense. Raising the temperature of the steam at a given pressure also means that less steam is needed to provide the same amount of energy. Efficiency will also vary, depending on the turbine, and other factors, such ascondenser vacuum. In general, running a pressure around 40 - 45 PSI, it will take 20,000 - 25,000 pounds of steam per hour to generate one megawatt of electricity during that hour. This is with steam that is just above saturation (around 285°F). So, for 5 MW, you'd need around 100,000 pounds of steam an hour. The pipe size would depend on the turbine. A 55 MW turbine (common for geothermal), might have two pipes bringing steam in (one per side), both of which are around 30" in diameter. For 100,000 pounds of steam an hour, much smaller pipes would suffice. However, expanding and then compressing the steam repeatedly is something you want to avoid. Note that these figures reflect more of a geothermal application. The pressure and temperature of steam from a boiler will typically be much higher.
q = mC∆Tq = heat = J m = mass of H2O = 4.5 g C = specific heat for H2O = 4.184 J/g/deg ∆T = change in temp = 140ºC q = (4.5 g)(4.184 J/g/deg)(140 deg) q = 2636 J of heat needed
more detail needed of how much heat to absorb and size available .
when steam is at its saturation point for a given pressure, any heat removed will cause liquid water to form. So when saturated steam is used to heat something else, the heated object/substance receives the condensation heat of the steam. The latent heat of condensation/evaporation is 970 But/lb @ 0 psig. On the other, superheated steam only gives up about 10 BTU/lb if it is cooled 20 degrees F. That means that much more steam would be used to transfer the equivalent amount of heat. The liquid water interface also improves the heat transfer.
80 Kgs