16020
The sum of the numbers in each row of Pascal's triangle is twice the sum of the previous row. Perhaps you can work it out from there. (Basically, you should use powers of 2.)
the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc.......... the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc..........
The sum of the numbers in the nth row of Pascal's triangle is equal to 2^n. Therefore, the sum of the numbers in the 100th row of Pascal's triangle would be 2^100. This formula is derived from the properties of Pascal's triangle, where each number is a combination of the two numbers above it.
When evaluating row n+1 of Pascal's triangle, each number from row n is used twice: each number from row ncontributes to the two numbers diagonally below it, to its left and right. From this it is easily seen that the sum total of row n+1 is twice that of row n. The first row of Pascal's triangle, containing only the single '1', is considered to be row zero. Its total, 1, is given by 20. From the above observations, we can conclude that the total of row n is given by 2n. For the eleventh row: 211 = 2048.
16020
Sum of numbers in a nth row can be determined using the formula 2^n. For the 100th row, the sum of numbers is found to be 2^100=1.2676506x10^30.
The sum of the numbers in each row of Pascal's triangle is twice the sum of the previous row. Perhaps you can work it out from there. (Basically, you should use powers of 2.)
The sum of the numbers on the fifteenth row of Pascal's triangle is 215 = 32768.
the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc.......... the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc..........
The sum of the numbers in the nth row of Pascal's triangle is equal to 2^n. Therefore, the sum of the numbers in the 100th row of Pascal's triangle would be 2^100. This formula is derived from the properties of Pascal's triangle, where each number is a combination of the two numbers above it.
8000 Numbers are: 381 383 385 387 389 391 393 395 397 399 401 403 405 407 409 411 413 415 417 419
64
=SUM(A1:A17) for example
Let's calculate the sums of few first rows of Pascal's triangle: 1st row: 1 = 1 2nd row: 1 + 1 = 2 3rd row: 1 + 2 + 1 = 4 Looks promising, let's continue: 4th row: 1 + 3 + 3 + 1 = 8 5th row: 1 + 4 + 6 + 4 + 1 = 16 We can make an assumption that each row's sum is twice the sum of previous row - it's a power of two. But why is that? If you know how Pascal's triangle is constructed, you should notice that when creating new row, you use the previous row numbers(except ones) two times in addition. Considering ones, you only use each 1 in previous row once, but in the new row you always add two 1's on the sides. Alternatively, you may think of empty space around Pascal's triangle as zeros and then you'll definitely use each previous row's numbers two times to create a new row. The formula will be then: s = 2n-1, where s - sum of the nth row(we assume numeration starts with 1 for the single '1' on the top) n - number of the row
18 + 19 + 20 = 57
It you select the blank cell under a column of numbers or a blank cell at the end of a row of numbers and hit the Autosum button it will enter the SUM function and select the cells above in the column, or to the left in a row. Pressing Alt and the = key will also do the same thing. If you select the column or the row with the numbers and click the button or do Alt and the = key, then it will also do the same.