Pipe Diameter = 3 Inches = .25 Ft Area of Circle = Pi X D X D / 4 - where D is Diameter and Pi is 3.14159 Volume of Pipe = Length X Area = or= 1 Foot X Area Volume = [1 Ft] X [ Pi X .25 X .25 ] / 4 Volume = 0.049087 Ft3 If the 3-inch Pipe flows at 1 Foot per second, then it will carry 0.049087 Cubic Feet per second.
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Weight of 50ft section of 3 inch hose with water in it?
There need not be any water at all in the hose! The capacity of the hose is 3.41 cubic feet.
All else being equal, a 2-inch hose carries 4 times the volume as a 1-inch hose.
That section of hose holds 25.5 gallons of water when it's full, which weighs about 213 pounds. To that, add the weight of the empty hose, which I don't know.
To calculate the volume of water held by the hose, we first need to find the cross-sectional area of the hose. The formula for the area of a circle is A = πr^2, where r is the radius of the hose (which is half the diameter). In this case, the radius is 0.75 inches. Converting the radius to feet (0.0625 feet), we can calculate the area of the hose's cross-section. Multiplying the cross-sectional area by the length of the hose (100 feet) gives us the volume of water held by the hose.