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To calculate the volume of water held by the hose, we first need to find the cross-sectional area of the hose. The formula for the area of a circle is A = πr^2, where r is the radius of the hose (which is half the diameter). In this case, the radius is 0.75 inches. Converting the radius to feet (0.0625 feet), we can calculate the area of the hose's cross-section. Multiplying the cross-sectional area by the length of the hose (100 feet) gives us the volume of water held by the hose.
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How much water does a hose carry that is one and 34 inches in diameter times 100 feet?
I assume you mean 1 and 3/4 inches in diameter. Therefore your cross-sectional area of your hose is pi/4*diameter. You can either leave your diameter in inches or convert it to feet. If you choose to leave you number in inches then you convert 100 ft to 1200 in and multiple 1200*cross-sectional area to get the cubic inches water in the hose. If you choose to convert your diameter to feet then just multiply 100 ft times cross-sectional area to get the cubic ft of water in the hose.
How much does a 100 ft section of 2.5 inch in diameter fire hose weigh with water?
That section of hose holds 25.5 gallons of water when it's full, which weighs about 213 pounds. To that, add the weight of the empty hose, which I don't know.
How much does a 50 ft section of 5 inch diameter fire hose weight?
109 lbs with no water
How much water does a 3 inch hose carry per foot?
Pipe Diameter = 3 Inches = .25 Ft Area of Circle = Pi X D X D / 4 - where D is Diameter and Pi is 3.14159 Volume of Pipe = Length X Area = or= 1 Foot X Area Volume = [1 Ft] X [ Pi X .25 X .25 ] / 4 Volume = 0.049087 Ft3 If the 3-inch Pipe flows at 1 Foot per second, then it will carry 0.049087 Cubic Feet per second.
What is the volume of 50 feet of 2.5 inch hose?
50 feet of 2.5-inch diameter hose has a volume of: 1.7 cubic feet (12.72 liquid gallons)
